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From:Miller, Terion Date:Wed Jul  1 15:10:09 2009
Subject:Re: Select and compare problems still ...



On 7/1/09 10:06 AM, "Phpster" <phpster@gmail.com> wrote:






On Jul 1, 2009, at 10:56 AM, "Miller, Terion" <tmiller@springfi.gannett.com
> wrote:

> Why doesn't this work?
>
>
> $query = "SELECT * FROM `restaurants` WHERE name ='$ucName' AND
> address = '$ucAddress' " ;
>
> $result = mysql_query($query) or die(mysql_error());
>
>
> echo $result;
> $row = mysql_fetch_array ($result);
>
>
>
> $sql = "INSERT INTO `restaurants` (name, address, inDate, inType,
> notes,
> critical, cviolations, noncritical) VALUES (" ;
> $sql .= " '$ucName',
> '$ucAddress', '$inDate', '$inType', '$notes', '$critical',
> '$cleanViolations', '$noncritical')";
>
>
>
> $result = mysql_query($sql) or die(mysql_error());
>
> The error I keep getting is:
>
> You have an error in your SQL syntax; check the manual that
> corresponds to
> your MySQL server version for the right syntax to use
>
> And I have gone in the mySQL panel and let it make the query ....so
> I'm
> really stumped why it hangs ...
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>

Try removing the backticks from the tablename, I have found that if
you include the backticks around the table name and not the field
names, mysql will throw the occassional fit.

Bastien

Sent from my iPod

Removed them and still getting the same error....
It returns one record then spits out the error...weird.
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