From:	Alexander Schreijnders	Date:	Fri Jan  9 17:30:47 2004
Subject:	[HELP] Percent sign replacement.

Hi,

I have written the following code to parse the incoming text from a
<textarea> so that PHP chars like " or \ are replaced with their respective
alt-codes.

$strBodyText1 = $_POST['message'];
$strBodyText2 = str_replace(array("\'", '\"', '\\', "%%"), array('\'',
'&quot', '&#092', '&#037'), $strBodyText1);
printf($strBodyText);

This code work well until a percent sign (%) comes into action. Somehow it's
not recognised by the code and I get a huge printf() error.
The error is as followed:
  Warning: printf() [function.printf]: Too few arguments in
/home/users/g/i/gimmic/www/brugadvies/rtb/function.php on line 91

I have searched for a sollution, but couldn't find one. Any idea how this
issue can be resolved?

Thanks in advance for your effort!

Cheers,

Alexander