Re: Vitruvian Man - parts 1-6
Steveski <[email protected]> Sun, 21 Apr 2024 00:00:09 +0100
| Newsgroups | alt.babylon5.uk |
|---|---|
| Message-ID | <[email protected]> |
On 20/04/2024 18:17, FP wrote: > On 27/03/2024 14:57, D wrote: >> Wikimedia Commons - Da Vinci Vitruve (photo L. Viatour) 2,258 x 3,070 >> pixels, 5.81 MB: > ... >> "Vitruvius, the architect, says in his architectural work that the >> measurements >> of man are in nature distributed in this manner, that is 4 fingers >> make a palm, >> 4 palms make a foot, 6 palms make a cubit, 4 cubits make a man, 4 >> cubits make >> a footstep, 24 palms make a man and these measures are in his >> buildings. If you >> open your legs enough that your head is lowered by 1/14 of your >> height and raise >> your arms enough that your extended fingers touch the line of the >> top of your >> head, let you know that the center of the ends of the open limbs >> will be the >> navel, and the space between the legs will be an equilateral triangle" > ... >> * simplifying the value of "y", y/(y+2)=tan(10): y = >> 2sin(10)/(cos(10)-sin(10)); >> circle chord at top of square = 8sqrt(sin(10)/(cos(10)-sin(10))) = >> ~3.701451; >> >> 2arcTan((cos(10)-sin(10))sqrt(sin(10)/(cos(10)-sin(10)))/(cos(10)/2-sin(10))) >> is central angle of top circle sector ~99.316396 degrees; top >> circle sector >> area = >> pi(2sin(10)/(cos(10)-sin(10))+2)^2arcTan((cos(10)-sin(10))sqrt(sin(10) >> /(cos(10)-sin(10)))/(cos(10)/2-sin(10)))/180 = ~5.109973 square >> cubits; top >> circle segment area = >> pi(2sin(10)/(cos(10)-sin(10))+2)^2arcTan((cos(10)-sin >> >> (10))sqrt(sin(10)/(cos(10)-sin(10)))/(cos(10)/2-sin(10)))/180+(8sin(10)/(cos >> (10)-sin(10))-8)sqrt(sin(10)/(cos(10)-sin(10))) = ~2.200907 square >> cubits; > > Hi D! > > Hi! > > Welcome to the froup! > > If I follow your instructions, will I be constructing Leo's pic or are > these CAD instructions for developing a man? > > Cheers > > Frank Good grief! Activity! :-) -- Steveski