Re: printing words without newlines?

> <snip>
>I'm learning more AWK basics and wrote function to read file, sort,
>print.  I use GNU AWK (gawk) and its sort but printing is harder to get
>working than anything... separate lines work, but when I use printf() or
>set ORS then use print (for words one line) all awk outputs (on FreeBSD
>UNIX 14 and Slackware GNU/Linux 15) is a space (and not even newline
>before shell prompt)... is this normal (and I made mistake?) or am I
>approaching it wrong?  I recall BASIC prints new lines, but as I learned
>basic C and some derivatives, I'm used to newlines only being specified...
>------------------------------------------------------------------------
># print_file_words.awk
># pass filename to function
>BEGIN { print_file_words("data.txt"); }
>
># read two-column array from file and sort lines and print
>function print_file_words(file) {
># set record separator then use print
># ORS=" "
>  while(getline<file) arr[$1]=$0
>  PROCINFO["sorted_in"]="@ind_num_asc"
>  for(i in arr)
>  {
>    split(arr[i],arr2)
>    # output all words or on one line with ORS
>    print arr2[2]
>    # output all words on one line without needing ORS
>    #printf("%s ",arr2[2])
>  }
>}
> <snip>

I think you forgot that arr2 is now an array => you have to iterate over
it as well.  There were also a few other coding errors, ie. not closing
the data.txt file; not declaring local vars in print_file_words:

--
$ cat test.awk
BEGIN { print_file_words("data.txt") }

function print_file_words(file,  i,j) {
  ORS = " "
  PROCINFO["sorted_in"]="@ind_num_asc"
  while (getline <file >0)
    arr[$1] = $0
  close (file)

  for(i in arr) {
    split(arr[i],arr2)
		for (j in arr2)
      print arr2[j]
  }
  ORS = "\n"
  print ""
}

$ gawk -f test.awk
all are base belong to us your 
--

Probably this is not the best way of doing things but I think you're
mainly just experimenting with sorting/printing so..