Re: Comparing strings

Lewis <[email protected]>
Newsgroups alt.comp.lang.shell.unix.bourne-bash
Organization Miskatonic U
Message-ID <[email protected]>
In message <[email protected]> Michael F. Stemper <[email protected]> wrote:
> On 13/07/2021 12.46, ELCV wrote:

>> If I do this:
>> 
>> if [ "$1" != "FOO" ];
>>   then
>>         echo "I can backup the 2nd volume";
>> else
>>          exit;
>> fi
>> 
>> It works. But if I add an "or" condition as follows:
>> 
>> if [ "$1" != "FOO" ]   ||  [ "$1" != "BAR" ] ;

> I've never seen this syntax. I always thought that the "or"
> needed to be within the test, as in:

> if [[ "$1" != "FOO" ||$1 != "BAR" ]]

There's a difference between [[ ]] and [ ] ([[ ]] is superior and you
should probably just get used to using [[ ]] exclusively).

But the syntax used in the sample above is incorrect, i believe, as
single brackets require that you use -o for or.

you really only need to deal with single [ ] if you want to be
compatible with sh.

-- 
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