Re: wsprintf I64 - how to get it to include a plus sign ?

On Wed, 1/7/2026 3:14 PM, R.Wieser wrote:
> JJ,
> 
> [quote=me]
>> Scratch that question.
> 
> Scratch that.  I'd forgotten that I had changed my test value, and caused it 
> to fit into 4 bytes.  Changing it back to 5E+10 the displayed result showed 
> again a truncated 32-bit result
> 
> Strange that "%lld" was not rejected as unrecognised though ...
> 
> So, the question still stands :
> 
> Any idea how to have sprintf (crtdll) print a 64-bit decimal value ?
> 
> Regards,
> Rudy Wieser
> 
> 

I couldn't get my INT64_T to work, and I suspect I need to install
more packages in my mingw64 thingy. Adding the header files made no difference.

/* #include <stdint.h> */
/* #include <inttypes.h> */
#include <stdio.h>

/* gcc      -std=c99 -o wide.exe wide.c */
/* gcc -m64 -std=c99 -o wide.exe wide.c */

int main( void )
{
   wchar_t buf[100];
   /* int64_t i; */
   long long int i;

   i = 5000000000000 ;

   int len = swprintf( buf, 100, L"%s %+lld %s", L"Pack my box with ", i, L" liquor jugs" );
   printf( "Generated %d characters\n\n", len );

   wprintf(L"%ls\n\n", buf);
}

 UCRT64 ~
$ ./wide
Generated 45 characters

Pack my box with  +5000000000000  liquor jugs


UCRT64 ~

   Paul