Re: The simple essence of Proof Theoretic Semantics
dbush <[email protected]>
| Newsgroups | sci.logic,comp.theory,sci.math,comp.ai.philosophy |
|---|---|
| Organization | A noiseless patient Spider |
| Message-ID | <[email protected]> |
On 7/1/2026 2:53 PM, olcott wrote: > On 7/1/2026 1:34 PM, dbush wrote: >> On 7/1/2026 2:20 PM, olcott wrote: >>> On 7/1/2026 1:10 PM, André G. Isaak wrote: >>>> On 2026-07-01 12:01, olcott wrote: >>>>> On 7/1/2026 12:33 PM, dbush wrote: >>>>>> On 7/1/2026 10:40 AM, olcott wrote: >>>> >>>>>>> The truth value of (∀ x, S(x) ≠ x) does not exist in Q. >>>>>> >>>>>> In your own words, what does it mean for the truth value of >>>>>> statement to not exist in a formal system? >>>>>> >>>>> >>>>> The same thing as: "cats are animals" expressed in >>>>> English has no English meaning in Chinese. >>>>> >>>>> Until "cats are animals" is translated into Chinese >>>>> it is just random gibberish that has no meaning or >>>>> truth value in Chinese. >>>> >>>> But ∀ x, S(x) ≠ x *isn't* random gibberish in Q. It is a well-formed >>>> expression of Q that has a well-defined meaning. It just happens to >>>> be unprovable. If it were random gibberish no one would have >>>> entertained the question of whether it could or could not be proven >>>> in Q. >>>> >>>> André >>>> >>> >>> It has no finite sequence of inference steps between >>> the expression and the axioms of Q. This seems to >>> mean that (∀x, S(x) ≠ x) is ungrounded in the atomic >>> base of Q in many of the different ways that this >>> can be expressed by different PTS authors. >>> >> >> In other words, (∀x, S(x) ≠ x) is not provable in Q. >> > > In PTS that means the expression is undefined. > It does not mean that Q has undecidable sentences in PTS. In your own words, what do you think it means for an expression to be undefined, and what do you think it means for a formal system to have undecidable sentences? > >> So once again, you're saying the same thing as everyone else but using >> different words. > >