Re: The simple essence of Proof Theoretic Semantics
André G. Isaak <[email protected]>
| Newsgroups | sci.logic,comp.theory,sci.math,comp.ai.philosophy |
|---|---|
| Organization | Christians and Atheists United Against Creeping Agnosticism |
| Message-ID | <[email protected]> |
On 2026-07-03 12:12, olcott wrote: > On 7/3/2026 12:17 PM, André G. Isaak wrote: >> On 2026-07-03 10:48, olcott wrote: >>> On 7/3/2026 9:45 AM, André G. Isaak wrote: >>>> On 2026-07-02 23:02, olcott wrote: >>>>> On 7/1/2026 9:03 PM, olcott wrote: >>>>>> Q cannot do the ∀x without an infinite sequence of steps. >>>>> >>>>> So your phrasing is good: Q would need something like an infinite >>>>> sequence of steps (or a single principle that summarizes them) to >>>>> get the ∀x. Since formal proofs must be finite, and Q lacks the >>>>> tool (induction) that would allow a finite proof of the infinite >>>>> claim, the universal statement remains unprovable. >>>> >>>> I'm not sure why you are responding to yourself nor who 'your >>>> phrasing' refers to since you don't quote anyone. But, assuming >>>> we're still talking about ∀ x, S(x) ≠ x in Q, your reasoning is >>>> simply off. >>>> >>>> You *can* prove universally quantified claims in Q, just not that >>>> particular claim. >>>> >>> >>> What is the reason that (∀x, S(x) ≠ x) cannot be proved in Q? >> >> Because it isn't true in all models of Q, > Model theory has been expressly off-topic for > many weeks in every thread. Whenever you ignore > this the rest of your reply will be ignored. The rest of my post which you snipped and (presumably) ignored explained *why* you are wrong about this. PTS does not reject models or model theory. It simply doesn't rely on model-theoretic semantics. Q *requires* a model. André -- To email remove 'invalid' & replace 'gm' with well known Google mail service.