Re: Problem with Changing from $defout > $stdout
Shugo Maeda <[email protected]> Thu, 15 Sep 2005 00:12:02 +0900
| Newsgroups | gmane.comp.apache.mod-ruby |
|---|---|
| Message-ID | <[email protected]> |
Hi,
Ben Gribaudo wrote:
> I'm working on upgrading some Ruby 1.6.x to prepare for a web-server
> wide upgrade to 1.8.2 (We're still running under 1.6.x). $defout is
> obsolete in Ruby 1.8.2. In irb, $defout==$stdout, so I would think that
> I should be able to replace any usage of $defout in a script with
> $stdout. But it doesn't work!
>
> Take the code below. I would expect to be able use either "$defout =
> out" and "$defout = starting_stdout" OR "$stdout = out" and "$stdout =
> starting_stdout". However, only the $defout lines work
"$stdout = out" worked for me.
-- test.rbx -----------
def get_output
starting_stdout = $stdout
begin
out = Object.new
class << out
attr_reader :output
def write(value)
@output ||= ''
@output << value.to_s
end
alias << write
def flush(*args) end
end
## Either of these lines should result in the same effect, correct?
#$defout = out
$stdout = out
yield
ensure
## Again, these two lines are identical in function, right?
#$defout = starting_stdout
$stdout = starting_stdout
end
puts ($stdout==$defout)==false
return out.output
end
r = Apache.request
r.content_type = "text/plain"
r.send_http_header
p get_output {
print "foo\n"
}
-----------------------------
My environment is below.
mod_ruby/1.2.4
Ruby/1.8.3(2005-06-23)
> Interestingly, while $stdout==$defout is true in irb, it is false in
> mod_ruby as puts puts ($stdout==$defout)==false true.
$defout(rb_defout) was removed from C API of Ruby 1.8, so mod_ruby
only sets $stdout(rb_stdout) now.
Shugo