Re: Regular expression validation

I wrote a short perl script for you:

#!/usr/bin/perl

my $string1 = "now is the time for all good";  # ends with good
my $string2 = "now is the time for all good/"; # ends with good/
my $string3 = "now is the time for all good/men to come"; # ends with 
good/something

my $regex = "^(.*good)?(/)?(.*)\$";

if ($string1 =~ m/$regex/) {
     printf "string1 \$1=$1 \$2=$2 \$3=$3\n";
}

if ($string2 =~ m/$regex/) {
     printf "string2 \$1=$1 \$2=$2 \$3=$3\n";
}

if ($string3 =~ m/$regex/) {
     printf "string3 \$1=$1 \$2=$2 \$3=$3\n";
}

knute@knute-XPS-8700:~$ ./match.pl
string1 $1=now is the time for all good $2= $3=
string2 $1=now is the time for all good $2=/ $3=
string3 $1=now is the time for all good $2=/ $3=men to come

It might be simpler to capture the whole string and remove the /?  Some 
actual data to see what you are trying to do would be helpful.

^ - start
(.*good) - capture anything including the word good
?(/) - capture a / if there is one
?(.*)\$ - capture the remainder of the string if there is any

There may very well be differences between perl's regex and apache's.

knute...

On 11/10/25 14:36, Darryl Baker wrote:
> Is there a mailing list where I can ask regular expression help?
> 
> I want to match line that end with a word or the word and a slash or the 
> word slash anything ‘/(.*)$’
> 
> I know the last case but making sure the regex covers the first two 
> cases is what I am unsure about.
> 
> Examples:
> 
> https://www.example.com/foobar
> 
> https://www.example.con/foobar/
> 
> https://www.example.com/foobar/anything
> 
> *Darryl Baker, *GSEC, GCLD** (he/him/his)
> 
> Sr. System Administrator
> 
> Distributed Application Platform Services
> 
> *Northwestern University*
> 
> 4^th  Floor
> 
> 2020 Ridge Avenue
> 
> Evanston, IL  60208-0801
> 
> [email protected] <mailto:[email protected]>_
> 
> (847) 467-6674 <tel:+18474676674>
> 


-- 

Knute Johnson
[email protected]