Re: Retrieve url path (host name plus path)

[email protected]
Newsgroups gmane.comp.cms.lenya.user
Message-ID <[email protected]>
Hi --

Have you checked out the Cocoon wiki on input modules? The request input  
module should do what you want, eg  
{request:requestURI}?{request:queryString} would return the entire URL,  
including request params. If the Apache proxy messes with the headers, you  
can always set ProxyPreserveHost On.

Ref: [ http://wiki.apache.org/cocoon/InputModules ] (and no, it's not  
obsolete, although it says so at the top of the page).

Hope this helped,

/Petteri

On Apr 15, 2010 3:32pm, Florent André <[email protected]>  
wrote:
> Hi all,



> As I currently work on google's sitemap generation, I have to know the

> host name and path of the request.



> I have a look into inputs modules but I only see one that gave information

> about "lenya document" (required to have an uuid).



> In my use case, I don't have a lenya doc... Here comes the design main

> lines :



> - url finish with sitemap.xml (for example http://example.com/sitemap.xml

> , http://www.example.com/toto/foo/sitemap.xml)



> - publication's sitemap.XMAP intercept sitemap.xml ending and mount a

> sitemap.xmap in seo module



> - in seo module, I have

> -- a match on sitemap.xml

> -- a navigation module generator

> -- a navigationToSitemap transformer



> - into this transformer I have to know the entire url for generate a good

> sitemap.xml, I think to do this throw a
> value="{anInputModule:key}">



> The base url retrive have to be "proxyied", have to be the same as the

> client see...



> Any help would be great appreciated,



> Have a good day

> ++



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