[Lenyacms-users] (new user)Problems with running wyona on Tomcat-4.1.24-LE-jdk14

I'm new to wyona.org software and I'm tring to get wyona cms (lenya) work on 
windows xp pro with:

* jsdk1.4.1_02
* apache-ant-1.5.3
* jakarta-tomcat-4.1.24-LE-jdk14

CATALINA_BASE:   C:\jakarta-tomcat-4.1.24-LE-jdk14
CATALINA_HOME:   C:\jakarta-tomcat-4.1.24-LE-jdk14
CATALINA_TMPDIR: C:\jakarta-tomcat-4.1.24-LE-jdk14\temp
JAVA_HOME:       C:\j2sdk1.4.1_02

CLASSPATH: %JAVA_HOME%\lib\classes.zip;

I've downloaded lenya-0.8-dev-bin-20030417045044.zip and put lenya.war in webapps 
folder. During starting up tomcat I got: 

2003-04-17 22:55:59 org.apache.commons.modeler.Registry loadRegistry
INFO: Loading registry information
2003-04-17 22:55:59 org.apache.commons.modeler.Registry getRegistry
INFO: Creating new Registry instance
2003-04-17 22:56:00 org.apache.commons.modeler.Registry getServer
INFO: Creating MBeanServer
2003-04-17 22:56:02 org.apache.coyote.http11.Http11Protocol init
INFO: Initializing Coyote HTTP/1.1 on port 8080
Starting service Tomcat-Standalone
Apache Tomcat/4.1.24-LE-jdk14
log4j:ERROR setFile(null,true) call failed.
java.io.FileNotFoundException: \WEB-INF\logs\log4j.log (...  ...)
        at java.io.FileOutputStream.openAppend(Native Method)
        at java.io.FileOutputStream.<init>(FileOutputStream.java:174)
        at java.io.FileOutputStream.<init>(FileOutputStream.java:102)
        at org.apache.log4j.FileAppender.setFile(FileAppender.java:272)
        at org.apache.log4j.RollingFileAppender.setFile(RollingFileAppender.java
:156)
        at org.apache.log4j.FileAppender.activateOptions(FileAppender.java:151)
        at org.apache.log4j.config.PropertySetter.activate(PropertySetter.java:2
48)

It looks like I forgot about some configuration issues, but what configuration ?!

and when I opened http://localhost:8080/leyna I got:

Cocoon 2 - Internal server error

--------------------------------------------------------------------------------

type fatal

message null

description No details available.

sender org.apache.cocoon.servlet.CocoonServlet

source Cocoon servlet

cause

org.apache.xml.utils.WrappedRuntimeException: The output format must have a 
'{http://xml.apache.org/xslt}content-handler' property!

request-uri

/lenya/index.html

path-info

index.html


Can anybody help me ?!


JL.
[email protected]