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This is an issue that I (and I think Brian) were asking about some time
ago, but I can't seem to find any final resolution to it in the threads
surrounding it in the mail archive. The basic question is "How can you
store a derived view?".
At one point I thought that you could do something clever with
view.union(), but all of these operations just create another derived
view. Is there no simple way to (a) create a derived view and (b) put it
in a storage? Is the only way to do this to create the new storage, the
new view, and then populate the view with a row-by-row copy via append()?
Is there a way to use append() (via the Python wrapper) with a row object
instead of a sequence or keyword/value arguments?
What I'm currently faced with is a very large storage (about 2.5 million
rows) and I would initially like to "subset" this into another storage
file.
Beyond that, it looks as though I'll ultimately be looking at a storage
with that many rows and, say 20,000 properties per row. And I'll want to
create and save derived views from that as well.
Suggestions?
--------------------------------------
Gary H. Merrill
Director and Principal Scientist, New Applications
Data Exploration Sciences
GlaxoSmithKline Inc.
(919) 483-8456
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