Re: display query results

See, you're working with a database - you execute a query but the data 
(result) is still in the database. The '$result' variable represents 
just a link to the data in the database - that's why it prints 'Resource 
id #3'. That's almost the same as the '$connection' variable - I guess 
you don't expect this to print all the data in the database:

<?php

$connection = pg_connect('...');
echo $connection;

?>

So you have to fetch the data from resultset from the database process 
into PHP, and that's what pg_fetch_* functions are for. Each time you 
call pg_fetch_array($result) it fetches and returns the next row (or 
FALSE if there are no more rows).

The rows returned by pg_fetch_array are associative arrays, keys being 
the field names.

So something like this should work:

<?php

$connection = pg_connect('...');
$result = pg_query('SELECT field_a, field_b FROM my_table');

while ($row = pg_fetch_array($result)) {

    echo 'field a: ', $row['field_a'],"\n";
    echo 'field b: ', $row['field_b'],"\n\n";

}

?>

If it prints nothing, then the resultset is empty - try to run the same 
query pro psql or some other SQL interface.

Tomas


> Doesn't work... and I feel totally lost. I don't understand the 
> pg_fetch_* stuff at all.
> One would think that my query should return the text that is in the 
> field. The database is quite correct and does work with php since it 
> comes from an older web-site that someone else programmed for me. I'm 
> using it to practice and learn. :)
> 
> Matthias Ritzkowski wrote:
>> Try this:
>>
>> $db = pg_connect("host=localhost port=5432 dbname=med user=med
>> password=0tscc71");
>>
>>          if (!$db)
>>          {
>>          die("Could not open connection to database server");
>>          }
>>
>>           // generate and execute a query
>>          $query = "SELECT description FROM glossary_item WHERE
>>  name='Alcohol'";
>>          $result = pg_query($db, $query) or die("Error in query: $query.
>>          " . pg_last_error($db));
>>
>>          // Print result on screen
>> while ($line = pg_fetch_array($result, null, PGSQL_ASSOC)) {
>>    foreach ($line as $col_value) {
>>         echo $col_value."<br />";
>>     }
>>
>>          pg_close($db);
>>
>>
>> The result set is an array, You just need to loop through it. The php
>> manual has some nice examples that helped me get started.
>> --------------------------------
>>
>>
>> Matthias Ritzkowski
>>
>>   
> 
> 


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