Re: How does bochs calculate the eip after executing an instruction ?

I could see three possible reasons:

1. This is not an instruction you think of and it is 3-byte length. You
didn't show opcodes so I cannot help you here.
2. The instruction is "jmp .+1" :)
3. Very unlikely - bug in Bochs

Stanislav

-----Original Message-----
From: horseriver [mailto:[email protected]] 
Sent: Wednesday, January 23, 2013 3:11 AM
To: [email protected]
Subject: [Bochs-developers] How does bochs calculate the eip after executing
an instruction ?

hi:

   I am debuging kernel with bochs , and find a problem .

   Here is an instruction at address 0x1110,its length is 2 bytes.
   after bochs execute this instruction,eip should be 0x11102,but bochs
gives 0x1113 to me ?
   what is the probable reason ?

thanks! 

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