ECDSA Signature
Ricardo Alex <[email protected]> Wed, 8 Nov 2023 07:33:17 -0800 (PST)
| Newsgroups | gmane.comp.encryption.cryptopp |
|---|---|
| Message-ID | <[email protected]> |
------=_Part_6970_565565378.1699457597937 Content-Type: multipart/alternative; boundary="----=_Part_6971_2019324777.1699457597937" ------=_Part_6971_2019324777.1699457597937 Content-Type: text/plain; charset="UTF-8" This code gives me a signature r,s std::string signaturehex; StringSource ss2(message, true, new CryptoPP::SignerFilter(prng, signer, new CryptoPP::HexEncoder( new CryptoPP::StringSink(signaturehex)))); I understand that r is the x coordinate of a point R in the eliptic curve, considering I have private key, public key r,s values of the signature and the message signed, is it possible to find the Y coordinate of point R? Thanks, -- You received this message because you are subscribed to the Google Groups "Crypto++ Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/cryptopp-users/c4e90455-cc93-4eef-a4e5-bee15a83ae2dn%40googlegroups.com. ------=_Part_6971_2019324777.1699457597937 Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable This code gives me a signature r,s=C2=A0<div><br /></div><div>std::string s= ignaturehex;<span style=3D"white-space: pre;"> </span><br />StringSource ss= 2(message, true,<br /><span style=3D"white-space: pre;"> </span>new CryptoP= P::SignerFilter(prng, signer,<br /><span style=3D"white-space: pre;"> </sp= an>new CryptoPP::HexEncoder(<br /><span style=3D"white-space: pre;"> </sp= an>new CryptoPP::StringSink(signaturehex))));<br /></div><div><br /></div><= div>=C2=A0I understand that r is the x coordinate of a point R in the elipt= ic curve, considering I have private key, public key r,s values of the sign= ature and the message signed, is it possible to find the Y coordinate of po= int R?</div><div><br /></div><div>Thanks,</div> <p></p> -- <br /> You received this message because you are subscribed to the Google Groups &= quot;Crypto++ Users" group.<br /> To unsubscribe from this group and stop receiving emails from it, send an e= mail to <a href=3D"mailto:[email protected]">cryp= [email protected]</a>.<br /> To view this discussion on the web visit <a href=3D"https://groups.google.c= om/d/msgid/cryptopp-users/c4e90455-cc93-4eef-a4e5-bee15a83ae2dn%40googlegro= ups.com?utm_medium=3Demail&utm_source=3Dfooter">https://groups.google.com/d= /msgid/cryptopp-users/c4e90455-cc93-4eef-a4e5-bee15a83ae2dn%40googlegroups.= com</a>.<br /> ------=_Part_6971_2019324777.1699457597937-- ------=_Part_6970_565565378.1699457597937--