Re: The step-Over (next) command seems repetitively displaying same statement execution

Hello Eli,

I am sorry, I forgot to mention that.

Compilation command is: " gcc hello.c -g " thats it.
gcc version is: 4.6.3
gdb version is: GNU gdb (Ubuntu/Linaro 7.4-2012.04-0ubuntu2.1) 7.4-2012.04

Thanks,
- Jitendra Pawar

On Tue, Dec 22, 2015 at 9:51 PM, Eli Zaretskii <[email protected]> wrote:
>> Date: Tue, 22 Dec 2015 17:33:16 +0530
>> From: Jitendra Pawar <[email protected]>
>>
>> $ gdb -q a.out
>> Reading symbols from /home/jitendra/work/roughwork/a.out...done.
>> (gdb) br main
>> Breakpoint 1 at 0x40054c: file hello.c, line 9.
>> (gdb) run
>> Starting program: /home/itendrap/work/roughwork/a.out
>> warning: no loadable sections found in added symbol-file
>> system-supplied DSO at 0x7ffff7ffa000
>>
>> Breakpoint 1, main () at t.c:9
>> 9        c = (char*) malloc (12);
>> (gdb) n
>> 9        c = (char*) malloc (12);
>> (gdb) n
>> 11        memcpy(c, "Hello World", 12);
>> (gdb) n
>> 13        printf("%s\n", c);
>> (gdb) n
>> Hello World
>> 14    }
>> (gdb)
>> ------------------------------------------------------------------------
>>
>> Can anyone please explain whats going wrong here? Why the malloc
>> statement 'c = (char*) malloc (12);' gets repeated?
>
> What compilation command and switches did you use to compile this
> program?