Re: Viewing the address of an array in gdb

Yes you are right. It picked the glibc symbol name "buffer". 
No matters. I will change the name. I thought there is something wrong with the buffer I defined.
Thank you very much.


Regards,
Mahmood 




    On Friday, July 6, 2018, 4:36:41 PM GMT+4:30, Pedro Alves <[email protected]> wrote: 
If you can't change the program, you can work around this by
unloading the shared library symbols, so that gdb sees the
program's symbol again.  E.g.:

(gdb) start
Temporary breakpoint 1 at 0x40048b
Starting program: /home/pedro/tmp/buffer 

Temporary breakpoint 1, 0x000000000040048b in main ()
(gdb) info symbol &buffer
buffer in section .bss of /lib64/libc.so.6
(gdb) nosharedlibrary 
(gdb) info symbol &buffer
buffer in section .bss
(gdb) x /30x  &buffer
0x601040 <buffer>:      0x00000000      0x00000000      0x00000000      0x00000000
0x601050 <buffer+16>:  0x00000000      0x00000000      0x00000000      0x00000000
0x601060 <buffer+32>:  0x00000000      0x00000000      0x00000000      0x00000000
0x601070 <buffer+48>:  0x00000000      0x00000000      0x00000000      0x00000000
0x601080 <buffer+64>:  0x00000000      0x00000000      0x00000000      0x00000000
0x601090 <buffer+80>:  0x00000000      0x00000000      0x00000000      0x00000000
0x6010a0 <buffer+96>:  0x00000000      0x00000000      0x00000000      0x00000000
0x6010b0:      0x00000000      0x00000000
(gdb) 

Thanks,
Pedro Alves