Is 16-bit quantization of values / (sub-)millimetric error in grids (sometimes) acceptable ?
Even Rouault <[email protected]> Sun, 08 Dec 2019 16:10:08 +0100
| Newsgroups | gmane.comp.gis.proj-4.devel |
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| Message-ID | <29187200.ZMgZr9vmcM@even-i700> |
Hi, I'm experimenting with encoding grids with 16-bit integer values, with an offset and scale, instead of using IEEE 32-bit floats. There's some connection with my previous thread about accuracies of NTv2... Let's for example take the example of egm08_25.gtx. It is 149.3 MB large If converting it into a IEEE 32-bit float deflate-compressed (with floating- point predictor) tiled geotiff, it becomes 80.5 MB large (the compression method and floatin-point predictor are fully lossless. There's bit-to-bit equivalence for the elevation values regarding the original gtx file) Now observing that the range of values is in [-107,86], I can remap that to [0,65535] with an offset of -107 and scale of (86 - -107) / 65535 ~= 0.0029 The resulting deflate-compressed (with integer predictor) tiled GeoTIFF is now 23.1 MB large ! Looking at the difference between the unscaled quantized values and the original ones, the error is in the [-1.5 mm, 1.5 mm] range (which is expected, being the half of the scale value), with a mean value of 4.5e-6 metre (so centered), and a standard deviation of 0.85 mm After that experimentation, I found this interesting page of the GeographicLib documentation https://geographiclib.sourceforge.io/html/geoid.html which compares the errors introduced by the gridding itself and interpolation methods (the EGM model is originally a continuous model), with/without quantization. And one conclusion is "If, instead, Geoid were to use data files without such quantization artifacts, the overall error would be reduced but only modestly". Actually with the bilinear interpolation we use, the max and RMS errors with and without quantization are the same... So it seems perfectly valid to use such quantized products, at least for EGM2008, right ? Now looking at horizontal grids, let's consider Australia's GDA94_GDA2020_conformal.gsb. It is 83 MB large (half of this size due to the error channels, which are set to a dummy value of -1...) Converting it to a compressed tiled Float32 tif (without those useless error channels), make it down to 4.5 MB. And as a quantitized uint16 compressed tif, down to 1.4 MB (yes, almost 60 times smaller than original .gsb file). The maximum scale factor is 1.5e-7 arcsecond, hence a maximum error of 2.3 micrometre... I'm pretty sure we're several order of magnitudes beyond the accuracy of the original model, right ? In EPSG this transformation is reported to have an accuracy of 5cm. The fact that we get such a small scale factor is due to GDA94 -> GDA2020 conformal being mostly a uniform shift of ~1.8 m and that the grids is mentioned to "Gives identical results to Helmert transformation GDA94 to GDA2020 (1)" If we look at the France' ntf_r93.gsb, which has shifts of an amplitude up to 130m, the maximum error introduced by the quantization is 0.6 mm. I would tend to think this is also acceptable (given the size of that particular file is small, compression gains are quite neglectable, but this is mostly to look if we can generalize such mechanism). What puzzles me is that in https://geodesie.ign.fr/contenu/fichiers/documentation/algorithmes/notice/ NT111_V1_HARMEL_TransfoNTF-RGF93_FormatGrilleNTV2.pdf where they compare the NTv2 approach regarding their native 3D geocentric correction approach, they underline in red a sample point where the difference between the 2 models is 1.2 mm, as if it had really some importance. For that test point, using the quantized approach would increase this difference to 1.3 mm. But when looking at the accuracy reported in the grid at that point it is 1.6e-3 arc-second (which is the minimum value for the latitude error of the product, by the way), ie 5cm, so it seems to me that discussing about millimetric error doesn't make sense. In EPSG this transformation is reported to have an accuracy of 1 metre (which is consistent with the mean value of the latitude shift error) Now, let's look at the freshly introduced BWTA2017.gsb file. 392 MB large As a Float32 compressed geotiff: 73 MB (5.4x compression rate) As a Int16 compressed geotiff: 26 MB (15x compression rate) Maximum error added by quantization for latitude shift: 0.25 mm Minimum error value advertized for latitude shift: 1.61e-5 arc-second (not completely sure about the units...), ie 0.5mm Mean error value advertized for latitude shift: 6.33e-5 arc-second, ie 1.9mm Interestingly when looking at the ASCII version of the grid, the values of the shifts are given with a precision of 1e-6 arcseconds, that is 0.03 mm ! For Canadian NTv2_0.gsb, on the first subgrid, the quantization error is 0.9 mm for the latitude shift. The advertized error for latitude is in [0, 13.35 m] (the 0.000 value is really surprising. reached on a couple points only), with a mean at 0.27 m and stddev at 0.48 m. In EPSG this transformation is reported to have an accuracy of 1.5 metre ~~~~~~~~~~~~~ So, TLDR, is it safe (and worth) to generate quantized products to reducte by about a factor of 2 to 3 the size of our grids compared to unquantized products, when the maximum error added by the quantization is ~ 1mm or less ? or will data producers consider we damage the quality of products they carefully crafted ? do some users need millimetric / sub-millimetric accuracy ? Or do we need to condition quantization to a criterion or a combination of criteria like: - a maximum absolute error that quantization introduces (1 mm ? 0.1 mm ?) - a maximum value for the ratio between the maximum absolute error that quantization introduces over the minimum error value advertized (when known) below some value ? For the BWTA2017 product, this ratio is 0.5. For ntf_r93.gsb, 0.012. For NTv2_0.gsb, cannot be computed given sothe min error value advertized is 0... - or, variant of the above, a maximum value for the ratio between the maximum absolute that quantization introduces over the mean of the error value advertized (when known). For the BWTA2017 product, this ratio is 0.13. For ntf_r93.gsb, 5.5e-4. For NTv2_0.gsb, 3.3e-3 - and perhaps consider that only for products above a given size (still larger than 10 MB after lossless compression ?) ~~~~~~~~~~~~~~~~ Jochem mentionned in the previous thread that the Netherlands grids have an accuracy of 1mm. I'm really intrigued by what that means. Does that mean that the position of control points used to build the grid is known at that accuracy, both in the source and target systems, and that when using bilinear interpolation with the grid, one remains within that accuracy ? Actually both the rdtrans2008.gsb and rdtrans2018.gsb grids report an accuracy of 1mm, but when comparing the positions corrected by those 2 grids, I get differences above 1mm. echo "6 53 0" | cct -d 9 +proj=hgridshift +grids=./rdtrans2008.gsb 5.999476046 52.998912757 echo "6 53 0" | cct -d 9 +proj=hgridshift +grids=./rdtrans2018.gsb 5.999476020 52.998912753 echo "52.998912757 5.999476046 52.998912753 5.999476020" | geod -I +ellps=GRS80 -104d18'21.49" 75d41'38.51" 0.002 That's a difference of 2 mm. I get that difference on a few other "random" points. If applying the quantization on rdtrans2018.gsb, we'd add an additional maximal error of 0.6 mm. The grid being 1.5 MB uncompressed, and 284 KB as a losslessly compressed TIFF, quantization isn't really worth considering (reduces the file size to 78 KB) Even -- Spatialys - Geospatial professional services http://www.spatialys.com _______________________________________________ PROJ mailing list [email protected] https://lists.osgeo.org/mailman/listinfo/proj