Getting to the items of a UI::Items::RadioTree (fwd)

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Sorry, I posted this one to the wrong list previously.

--=20
    .--=3D ULLA! =3D---------------------.   `We are not here to give users=
 what
    \     http://cactus.rulez.org     \   they want'  -- RMS, at GUADEC 200=
1
     `---=3D [email protected] =3D---'
Ha nem j=F3 eredm=E9ny j=F6n ki, szorozd be az oldalsz=E1mmal.

---------- Forwarded message ----------
Date: Mon, 3 Oct 2005 17:13:34 +0200 (CEST)
From: Dr. ERDI Gergo <[email protected]>
To: GTKmm Mailing List <[email protected]>
Subject: Getting to the items of a UI::Items::RadioTree

Hi,

suppose I have the following menu structure:

     Gnome::UI::Items::Info m_viewmode[] =3D {
         Gnome::UI::Items::Item (_("_Sort by ID"));
         Gnome::UI::Items::Item (_("_Group by type"));
     };

     Gnome::UI::Items::Info m_view[] =3D {
         Gnome::UI::Items::RadioTree (m_viewmode)
     };

     Gnome::UI::Items::SubTree menubar[] =3D {
         Gnome::UI::Menus::View (m_view),
     };

     Gnome::UI::Items::Array<Gnome::UI::Items::SubTree> &infos =3D create_m=
enus=20
(menubar);

Now, how do I get the Gtk::Widget* of the 'Group by type' menu item? The=20
problem is, since UI::Items::RadioTree is a direct descendant of UI::Info, =
thus=20
having no accessor to its children. I.e. this can't be done:

     Gtk::Widget *foo =3D infos[0].get_uitree()[0].get_uitree()[1].get_widg=
et ();

So, what is a working solution?

Thanks,
 =09Gergo


--=20
    .--=3D ULLA! =3D---------------------.   `We are not here to give users=
 what
    \     http://cactus.rulez.org     \   they want'  -- RMS, at GUADEC 200=
1
     `---=3D [email protected] =3D---'
The best evolutionary trait an animal can have these days is either being c=
ute=20
or tasty.
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