Re: Can not transfer the video stream fastly!

I guess the problem is in the timestamp. If you want to send 10
packets per second, with RTP clock frequency 90khz, and each packet
encodes 100ms, in principle, you should increase the timestamp by 9000
for each packet.

On Sat, May 21, 2005 at 10:26:54AM +0700, Seven Pham wrote:
> Dear all!
> I 'm using the ccRTP to transfer the video stream. I set the
> scheduling timeout 100000 and the expire Timeout is 1000000 in the
> session send. And in the session receive , their value are 10000 and
> 1000000. The payload type is DynamicPayloadType(100, 90000). And this
> is the source code for sending:
> 
> #define PERIOD 100 //send 10fps
> #define PACKET_SIZE 176*144*3/2 //YUV frame
> TimerPort::setTimer(PERIOD);
> for( int i = 0 ; (count > 0) ; i++ ){
> 
>                         count = fread(buffer, 1, PACKET_SIZE, videoinput);
>                         if( count > 0 ){
>                                 // send an RTP packet, providing timestamp,
>                                 socket->putData(PACKET_SIZE*i,
> buffer,PACKET_SIZE);
>                         }
> 
>                         // Let's wait for the next cycle
>                         Thread::sleep(TimerPort::getTimer());
>                         TimerPort::incTimer(PERIOD);
>                 }
> But it can not send the packet as fast as i want to. it only send them
> approximately one frame per seccond. I checked the run() function in
> the rtp.h, the value timeout that it gets from the
> getSchedulingTimeout() function is not smaller 1000. so it can not
> call dispatchDataPacket() function to send out the packet.I don'n how
> to fix them, please help me.
> Thanks!
>       ---------------Seven Pham------------------
> 
> 
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