Re: BUG : mutiple and argoptional option fail to fill <opt>_args[0] with default value

Hi

since you also specify that 'argoptional' then the default value is not
set if you specify no argument to --foo, since the argument is optional,
so that option --foo is meant to be able to deal also with no argument
at all... that's how I interpreted the semantics when I implemented it.

Does it make sense?

hope to hear from you soon
cheers
	Lorenzo

P.S. please take a look at the current open (and closed) bugs to make
sure that this issue has already been raised.

On 10/19/2012 10:57 AM, Fr=E9d=E9ric Heitzmann wrote:
> Hi all,
> =

> I defined and option like this :
> =

> option "foo" - "bla bla bla" string typestr=3D"STR" default=3D"default_fo=
o"
> argoptional multiple optional
> =

> If I call with --foo, the default value is not added to foo_args[0].
> Actually, foo_args[0] is a NULL pointer, while I expected that
> foo_args[0] would be string "default_foo".
> =

> If I remove 'default', and set --foo without any argument, this time
> foo_args[0] is set to "default_foo".
> =

> The documentation says :
> "If it is known that a multiple option has a default value, then it can
> be safely assumed that the first element of generated array
> |<option>_arg| is always set. "
> =

> so it really looks like a bug to me.
> =

> Can someone confirm ?
> I may work on a patch if it helps.


-- =

Lorenzo Bettini, PhD in Computer Science, DI, Univ. Torino
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