how to restrict variables under 1e-3

Hi, all!

I need to solve a problem in witch some statements may restricts a variable
above a small value, e.g. 1e-4. But after solving, GLPSOL is setting this
variable equals to zero.

If I run this problem using "--exact" argument, it works as expected, but
it uses much more memory. Is there any argument or work arround to o run
this problem in glpsol without using exact arithimetic?

*Example:*
In the simple example attached, the minimun value for "x" must be
"delta_min", but in my tests:
if delta_min < 1e-3, x results in 0 (even for delta_min = 9.999e-4)

*(1) - Using "statement_test_0.0001.dat" file, the result is wrong:*
3 rows, 1 column, 3 non-zeros
Preprocessing...
~     0: obj =  0.000000000e+000  infeas = 0.000e+000
OPTIMAL SOLUTION FOUND BY LP PREPROCESSOR
Time used:   0.0 secs
Memory used: 0.1 Mb (88615 bytes)
Display statement at line 14
x.val = 0
x = 0.0000000000000000
Display statement at line 17
delta_min = 0.0001
Display statement at line 18
delta_max = 0.0002
Model has been successfully processed

*(2) - Using "statement_test_0.001.dat" file, the result is correct:*
3 rows, 1 column, 3 non-zeros
Preprocessing...
~     0: obj =  1.000000000e-003  infeas = 0.000e+000
OPTIMAL SOLUTION FOUND BY LP PREPROCESSOR
Time used:   0.0 secs
Memory used: 0.1 Mb (88615 bytes)
Display statement at line 14
x.val = 0.001
x = 0.0010000000000000
Display statement at line 17
delta_min = 0.001
Display statement at line 18
delta_max = 0.002
Model has been successfully processed

*(3) - Running (1) with "--exact" argument, the result is correct, but uses
more memory:*
glp_exact: 3 rows, 1 columns, 3 non-zeros
GLPK bignum module is being used
(Consider installing GNU MP to attain a much better performance.)
      0:   infsum =                 0.0001   (0)
      1:   infsum =                      0   (0)
*     1:   objval =                 0.0001   (0)
*     1:   objval =                 0.0001   (0)
OPTIMAL SOLUTION FOUND
Time used:   0.0 secs
Memory used: 0.1 Mb (92819 bytes)
Display statement at line 14
x.val = 0.0001
x = 0.0001000000000000
Display statement at line 17
delta_min = 0.0001
Display statement at line 18
delta_max = 0.0002
Model has been successfully processed

Thanks for your help!

Att,
Thiago Henrique Neves

-- 
Thiago H. Neves
(31) 98608-0666

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