Alternating results on spacing on nested parentheses on the first statement of a function with a pointer

Hello! I have found an inconsistency in how indent handles nested 
parentheses, as the email subject says. I've tried to work out what 
causes and doesn't cause it below:


  indent -linux indent.c result 1

void bug_1(int (*parentheses_pointer), int after)
{
	 ((0 == 0) || (0 == 1));
}

void bug_2(int (*parentheses_pointer))
{
	if ((0 == 0) || (0 == 1))
		return;
}

void bug_3(int before, int (*parentheses_pointer))
{
	 ((0 == 0) || (0 == 1));
}

void bug_4(int (*parentheses_pointer), int after)
{
	 ((0 == 0) || (0 == 1));
}

void bug_5(void (*function_pointer)(void))
{
	((0 == 0) || (0 == 1));
}

void fine_1(int variable)
{
	((0 == 0) || (0 == 1));
}

void fine_2(int (*parentheses_pointer))
{
	statement();
	((0 == 0) || (0 == 1));
}

void fine_3(int *normal_pointer)
{
	((0 == 0) || (0 == 1));
}


  indent -linux indent.c result 2

void bug_1(int (*parentheses_pointer), int after)
{
     ( (0 == 0) ||(0 == 1));
}

void bug_2(int (*parentheses_pointer))
{
     if( (0 == 0) ||(0 == 1))
         return;
}

void bug_3(int before, int (*parentheses_pointer))
{
     ( (0 == 0) ||(0 == 1));
}

void bug_4(int (*parentheses_pointer), int after)
{
     ( (0 == 0) ||(0 == 1));
}

void bug_5(void (*function_pointer)(void))
{
      ( (0 == 0) ||(0 == 1));
}

void fine_1(int variable)
{
     ((0 == 0) || (0 == 1));
}

void fine_2(int (*parentheses_pointer))
{
     statement();
     ((0 == 0) || (0 == 1));
}

void fine_3(int *normal_pointer)
{
     ((0 == 0) || (0 == 1));

}


I hope this helps! Thanks for everything GNU! <3