Re: why this indent result looks abnormal? when i drop the cast operator from source, it works well? why

Looks like you've found a bug.
I'll have to investigate.

D

??? wrote:
> line 38 in attachment
>   
> ------------------------------------------------------------------------
>
>      1	Script started on 2007Äê08ÔÂ16ÈÕ ÐÇÆÚËÄ 09ʱ43·Ö40Ãë
>      2	sgb@oracle /tmp>bash -version
>      3	GNU bash, version 3.00.15(1)-release (i386-redhat-linux-gnu)
>      4	Copyright (C) 2004 Free Software Foundation, Inc.
>      5	sgb@oracle /tmp>uname -a
>      6	Linux oracle.dev 2.6.9-22.ELsmp #1 SMP Mon Sep 19 18:32:14 EDT 2005 i686 i686 i386 GNU/Linux
>      7	sgb@oracle /tmp>indent -version
>      8	GNU indent 2.2.9
>      9	sgb@oracle /tmp>cat ~.//.indent.pro
>     10	-ppi3
>     11	-ip3
>     12	-psl
>     13	-sc
>     14	-sob
>     15	-pcs
>     16	-bap
>     17	-bad
>     18	-bbb
>     19	-ci2
>     20	-ncdw
>     21	-nce
>     22	-i2
>     23	-gnu
>     24	-hnl
>     25	-cs
>     26	sgb@oracle /tmp>cat ./test_indent.sh 
>     27	echo "void printGathShm (void *base) 
>     28	{ for (i = 0; i < MAX_ARRAY_SIZE; i++) { 
>     29	p = (char *) base + i; }}" |
>     30	indent -st
>     31	sgb@oracle /tmp>sh ./test_indent.sh 
>     32	void
>     33	printGathShm (void *base)
>     34	{
>     35	  for (i = 0; i < MAX_ARRAY_SIZE; i++)
>     36	    {
>     37	      p = (char *) base + i;
>     38	}}
>     39	sgb@oracle /tmp>exit
>        
>     40	Script done on 2007Äê08ÔÂ16ÈÕ ÐÇÆÚËÄ 09ʱ45·Ö07Ãë
>   
> ------------------------------------------------------------------------
>
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