Re: How does one define a closure in m4?

Doug McIlroy wrote:
> specialize(unary,binary,value) produces a unary operation
> by fixing the value of one the operands of a binary operation.
>
> define(add,`($1+$2)')
> define(div,`($1/$2)')
> define(specialize,`define($1,`$2('$`1,$3)')')
> specialize(succ,`add',1)
> specialize(half,`div',2)
>
> With these definitions, half(succ(4)) expands to ((4+1)/2)
Thanks, Doug! Works for me.

Now I've got closure on closures! :)

-- 
Jack J. Woehr     # For in the idea of chess and the development
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www.softwoehr.com # intellectual struggle of mankind. – Richard Reti