RE: why does command echo \\\foobar print \\foobar

Well, what you sent me prints correctly, so it must be the Windows port of GNU that is doing this

> With the makefile
> 
> foobar:
>                 echo \\\foobar
> why 
> 
> C:\Temp>make foobar
> \\foobar
> 
> Where is this explained in the manual?

Paul says:  (...) then there's a bug in GNU make's fast-path
backslash handling for Windows systems.


But Paul, one more thing, where does it say in the manual, that it should be \foobar (one slash).  I only see, that \\ at the _end_ of the command, is escaped, but from my reading of the manual, it seems to indicate that this is only for the end, in the middle of a command, \ is not any special.