Re: why does command echo \\\foobar print \\foobar

> From: "Mark Galeck (CW)" <[email protected]>
> Date: Sun, 7 Feb 2010 10:41:36 -0800
> Accept-Language: en-US
> acceptlanguage: en-US
> 
> 
> >This works for me: I see
> 
>     echo \\\foobar
>     \\\foobar
> 
> 
> OUCH!  I was using Cygwin echo, unknown to me (echo is not a executable in Windows, so the windows shell found the Cygwin echo, later in the path, and did not do the built in Windows echo).  
> 
> So now I see this:
> 
> Cygwin echo from Cygwin shell:
> 
> $echo \\\foobar
> \foobar
> 
> From windows shell:
> 
> C:\Temp>c:\tools\cygwin\bin\echo \\\foobar
> \\\foobar
> 
> 
> And from within GNU make
> 
> SHELL=cmd.exe 
> 
> foobar:
> 		echo \\\foobar
> 
> C:\Temp>make foobar
> echo \\\foobar
> \\foobar
> 
> 
> I can kind of understand the first two behaviours:  the first, Cygwin echo within a Unix-like shell, tries to behave like Unix.  Second, within Windows, tries to be compatible with windows echo.  
> 
> But third, I still don't understand.  

As I say above, I cannot reproduce your third behavior.  Again, please
invoke Make with -d and show the results.