Re: Solve Simple Relationship

José Abílio Matos <[email protected]> Fri, 27 Aug 2021 22:17:04 +0100
Newsgroups gmane.comp.gnu.octave.general
Message-ID <2082883.Mh6RI2rZIc@griffin>
On Friday, 27 August 2021 16.09.33 WEST Thomas D. Dean wrote:
> I have a voltage divider I want to calibrate. I tried this by exchanging
> the resistors and measuring the resultant rfesistance.
> 
> 1.6516 = 3.3 * R1 / (R1 + R2)
> 1.6484 = 3.3 * R2 / (R1 + R2)
> 
> R1 is around 1005 ohms
> R2 is around 1003 ohms
> 
> I think this is simple.  But evidently, it is beyond me.
> 
> Tom Dean

As others said your equations are the same, that is

1.6516 = 3.3 * R1 / (R1 + R2) <=> 1.6484 = 3.3 * R2 / (R1 + R2)

So you do not have 2 but just 1 equation.

Note that 1.6516 + 1.6484 = 3.3.

So you really need another equation to resolve this problem. :-)
-- 
José Matos




----------
We are transitioning to a web based forum
for community help discussions at
https://octave.discourse.group/c/help