sort -d does not produce dictionary order

"Jeff Orrok" <[email protected]> Fri, 13 Jun 2003 23:48:03 -0700 (PDT)
Newsgroups gmane.comp.gnu.textutils.bugs
Message-ID <[email protected]>
[root@voc root]# sort --version
sort (textutils) 2.0.21
Written by Mike Haertel and Paul Eggert.

Copyright (C) 2002 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

Redhat Linux 7.3

According to the man page, -d gives dictionary order, which should count
blanks as coming before letters -- at least that's the way I was taught in
school.  However, using -d produces the same output as omitting -d.  When I
sort the parameters from the Samba smb.conf man page, part of what I get is:

       · config file
       · deadtime
       · debug hires timestamp
       · debuglevel
       · debug pid
       · debug timestamp
       · debug uid
       · default
       · default service

debuglevel belongs after debug uid.

Regards,

Jeff Orrok