cgicc: fastcgi question
Jay <[email protected]>
| Newsgroups | gmane.comp.gnu.utils |
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| Organization | http://groups.google.com |
| Message-ID | <16275a0e-533e-4070-a60a-b3726f4755cc@i12g2000prf.googlegroups.com> |
Good afternoon all, I'm using cgicc to do fastcgi. I can't figure out how to set the error code though. How does one return a 404 using fastcgi? This looks like the right routine: *---------------------------------------------------------------------- * * FCGX_SetExitStatus -- * * Sets the exit status for stream's request. The exit status * is the status code the request would have exited with, had * the request been run as a CGI program. You can call * SetExitStatus several times during a request; the last call * before the request ends determines the value. * *---------------------------------------------------------------------- void FCGX_SetExitStatus(int status, FCGX_Stream *stream) ... But it doesn't work. I tried all the three streams in the request structure: FCGX_SetExitStatus( 404, request.out ); Any suggestions?