Re: Compute values with 'every'

As commented previously you need to filter out also the points when you
define the y value.
So it should read:
file1 using (($0-3)/4):(int($0)%4 == 0 ? (y=$1,NaN) : int($0)%4 == 3 ? $1/y
: NaN) title "rr100/rr25" ls 9

like this it will plot NaN every 1st, 2nd and 4th line of your four line
data block and for line 3 it plots the data from line3 divided by data from
line 1.

Best,
Alex

On Thu, 3 Dec 2020 at 11:36, Robert von Knobloch <[email protected]> wrote:

> Oh dear! I wrote a little too soon Alex, sorry.
> The trace looks OK at first and then I realised that it had more plotted
> points that the number of data samples (twice as many). These are
> positioned at the integer points of samples on the X axis and also
> erroneously at 1/3 of the distance between these points. (So at X = 1,
> 1.33, 2 etc..)
> I cannot see where these points come from , any ideas?
>
> LG,
>
> Bob
>
> > On 02/12/2020 17:00, Alexander Stangl wrote:
> >> Das sollte jetzt klappen:
> >> statt using 0:... musst du using (($0-3)/4):... verwenden. Dann plottest
> >> du die daten gleich wie die anderen.
> >>
> >> LG
> >
> > Alexander, your solution works perfectly.
> > Again, many thanks for your efforts.
> > My knowledge of gnuplot is not as deep as yours.
> >
> > I'll post to the list as the topic is closed.
> > Bob (Robert) von Knobloch.
> >
> > Solution:
> >
> > set datafile missing NaN
> > y=NaN
> > plot  file1 every 4::0 using 1 title "rr25" ls 1, \
> >       file1 every 4::1 using 1 title "rr50" ls 3, \
> >       file1 every 4::2 using 1 title "rr75" ls 5, \
> >       file1 every 4::3 using 1 title "rr100" ls 7, \
> >       file1 using (($0-3)/4):(int($0)%4 == 0 ? (y=$1) : int($0)%4 == 3 ?
> $1/y
> > : NaN) title "rr100/rr25" ls 9
> >
> >
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>
>

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