How to initialize an array of struct?

Hi,

After spending more than one day to create an array of struct I have 
come to this code:

struct Lamp  {
   uint8_t highAddress [9] ;
   uint8_t lowAddress [9] ;
   uint8_t onoff ;
   uint8_t active ;
   uint8_t power;
   uint8_t brightness ;
   uint8_t temperatures ;
   uint8_t faultCount ;
} ;

struct Lamp lamps [10];


void init () {

   struct Lamp lamp0 = {" 0013A200 ", " 4094500D " , 0 , 1 , 0 , 0, 0 , 0} ;
   struct Lamp lamp1 = {" 0013A200 ", " 40B12530 " , 0 , 1 , 0 , 0, 0 , 0} ;
   struct Lamp lamp2 = {" 11111111 ", " 22222222 ", 0 , 0, 0 , 0, 0, 0 };
   struct Lamp lamp3 = {" 33333333 ", " 44444444 ", 0 , 0, 0 , 0, 0, 0 };
   struct Lamp lamp4 = {" 55555555 ", " 66666666 ", 0 , 0, 0 , 0, 0, 0 };
   struct Lamp lamp5 = {" 77777777 ", " 88888888 ", 0 , 0, 0, 0 , 0, 0 };
   struct Lamp lamp6 = {" 99999999 ", " 00000000 ", 0 , 0, 0, 0 , 0, 0 };
   struct Lamp lamp7 = {" AAAAAAAA ", " BBBBBBBB ", 0 , 0, 0, 0 , 0, 0 };
   struct Lamp lamp8 = {" CCCCCCCC ," " DDDDDDDD ", 0 , 0, 0, 0 , 0, 0 };
   struct Lamp lamp9 = {" EEEEEEEE ", " FFFFFFFF ", 0 , 0, 0, 0 , 0, 0 };

   lamps [0] = lamp0 ;
   lamps [1] = lamp1 ;
   lamps [2] = lamp2;
   lamps [3] = lamp3 ;
   lamps [4] = lamp4 ;
   lamps [5] = lamp5 ;
   lamps [6] = lamp6 ;
   lamps [7] = lamp7 ;
   lamps [8] = lamp8 ;
   lamps [9] = lamp9 ;
}

it compiles without errors ( and it may be that it works!) but it is 
certainly wrong because it consumes twice the memory required (once for 
the array [ 10] and another for 10 lamps).

The question is: how can I initialize the array without defining first 
ten lamps individually ?

Thank you very much .

-- 
Domenico Formenton
Tel. 06 92731757
Fax. 178 2250847
Cell. 333 7075929



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