Can -- Sampling time point of -- 87.5%

John cliffer <[email protected]>
Newsgroups gmane.comp.hardware.bus.can
Message-ID <CALuovX0JGVmGAGx85hVrrKSecRMTEBCBy5FcthyMg_2dArk-pQ@mail.gmail.com>
But still it tell's about how to calculate all the segments of an bit
 ......  but not what will be sample rate for this calculation as shown in
examples.

Can open standard say try to achieve about  87.5% sample rate for
acceptable performance on CAN bus.

Any suggestion for this ?


//John



On Wed, Dec 5, 2012 at 3:40 AM, YAP <[email protected]> wrote:

> On Tue, Dec 4, 2012 at 8:29 PM, John cliffer <[email protected]> wrote:
> > Hi,
> >
> > I am going through this good application note from philips AN1798.pdf.
> >>> 4.1 Step-by-Step Calculation of Bit Timing Parameters
> >
> > Here no where it is mentioned about achieving correct sampling time
> point.
> > Canopen suggest to use 87.5% sampling point
> >
> > 1> How shall we start the calculation of time quanta for segments to
> achieve
> > -- 87.5% sampling time point?
> > 2> What is the formula to calculate sample rate of bit ?
> >
> > Please suggest.
> >
> > //John
>
>
> IMO good paper here
> http://ww1.microchip.com/downloads/en/AppNotes/00754.pdf
>
>
> /Ake
>
> --
>  ---
> Ake Hedman
> eurosource, http://www.eurosource.se
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