Installing ISR for Interrupt 5

I'm trying to install a handler for Interrupt 5 and am ending up hanging my
machine when the interrupt gets generated.  I'm also installing a handler for
Interrupt 1 and this 1 is working OK, so I'm pretty sure I have the overall flow
right.  I think my problem is that Interrupt 5 is shared by the 1-wire master
bus and I can't find the documentation for turning off those interrupts.  The
documentation says I need to use OWMAD and OWMDR to turn off the EOWMI bit, but
I can't find anywhere that tells me where that bit is, or if there's anything
else I need to do.  I did infer that the control register is used to turn it
off, but there must be something else.  Here's my interrupt installation code:

  clr	EIE.0           ; disable int 5 (and 2-4)
  mov   OWMAD,#5	; Select 1-wire control register
  mov	OWMDR,#0	; Set EOWMI to disable the OW interrupts
  mov	dps, #1
  mov	dptr, #cardClockInt  ; address of ISR
  mov	dps, #0
  mov a, #43h           ; interrupt vectors for ints 2-5
  lcall System_InstallInterrupt
  jz	enableInt5
  setb  EIE.0
  mov	a,#4            ; error code - unable to install interrupt
  sjmp	Install_Exit  

enableInt5:
  setb	EIE.0
    ...


The routine to install the interrupt returns success (it would return 4 if this
installation failed).  Right now, the ISR is empty - just an IRET instruction,
but the board hangs as soon as the interrupt is generated.  As I said, my
handler for interrupt 1 is working, but (a) - interrupt 5 is shared with
interrupts 2-4, and (b) it is multiplexed with the 1-wire bus.  Is there
anything else I need to do when installing int 5?

Thanks for any help...

Chris Musial
cmusial-cK+/[email protected]

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