Re: NullPointerException in Socket

Hi,Shawn!!!
Thank you very much for your answer.
But I didn`t forget create ServerSocket at the begin of the programm.
try{
          ServerSocket listenSocket= new ServerSocket(SERVER_PORT);
          System.out.println("Socket is cool!");
        }
        catch (IOException excp)
        {
        System.err.println("Unable to listen port" + SERVER_PORT + ":" +excp);
        }
When I run this programm I see - "Socket is cool", but then at point described 
above I have NullPointerException.
Have you more ideas?
Excuse me ,but I need any help.

Thanks a lot.

В сообщении от Понедельник 03 Май 2004 21:29 вы написали:
> Hi, Dennis.  It looks like you've forgotten to create the ServerSocket
> object:
>
> 	listenSocket = new ServerSocket(some_port);
>
> Regards,
> 	-Shawn
>
> On 3-May-04, at 5:46 AM, Denis Yakovlev wrote:
> > Hi, All!
> > Can you help me with folowed problem? May be I just have poor
> > knowledge in
> > Java. So...
> > The problem:
> >  public ServerSocket listenSocket ;
> >
> > public void serveTini() {
> >          Socket clientSocket;
> >                 try{
> >                         System.out.println("Point1");
> >                         while(keepRunning){
> >                                 System.out.println("DeadPoint");
> >                                  clientSocket = listenSocket.accept();
> > <----
> >
> >  at this point I have an error:
> >
> > java.lang.NullPointerException
> >    in SockTiniTerm.serveTini(@JPC=b0010)
> >       in java.lang.System.???
> >
> > What should I do? Is syntax correct? Anybody please help me
> >
> >
> >
> > --
> > Best regards
> > Denis Yakovlev,

-- 
Best regards
Denis Yakovlev,
QA Engineer, SW-Soft
Tel:89059564660
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