Help with the SEC on an MCF5485
"Edwards, James - Centrilift" <[email protected]> Thu, 23 Apr 2009 10:47:46 -0500
| Newsgroups | gmane.comp.hardware.motorola.microcontrollers.coldfire |
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From: James Edwards <jamesDOTedwardsATcentriliftDOTcom>
To: [email protected]
Subject: PROBLEM WITH LOADING PRODUCT
Help with the SEC on an MCF5485
--------------------------------------------------------------
Hi WildeRice Gang,
This is my first post. I was pointed here by Bob McMillan at Future
Electronics. He said a lot of good things about the list.
My Problem is that I'm having some grief figuring out how to use the
Security Encryption Controller (SEC) on the MCF5485.
I've asked for some help on the FreeScale Forum but have not received
any so I'm sending this to out you. In the hope that some of you have
already conquered the SEC. I would like to use the SEC to calculate an
MD5 check sum for a file.
You can check out my post, and all my replied to myself on the FreeScale
Message board at the link below (I Hope it is OK to link to their
message board on the wildrice list)
http://forums.freescale.com/freescale/board/message?board.id=3DCFCOMM&thr=
e
ad.id=3D6638
I've pasted a few snippets of C code in there. It's getting too long to
paste into an email. If you want to / need to see the source files let
me know and I'll send them to you.
As of today I've stopped statically assigning both Crypto channels to
the MDEU during initialization because I was getting a channel already
assigned error. I think the Header for the first Descriptor just goes
out and grabs the MDEU if it is not already in use anyway.
Now I'm stuck just after loading Fetch Register Zero (FR0) with a
pointer to the Head of my first Descriptor (the Descriptor structure and
how I'm building the Descriptor chain are on the link above) I'm not
seeing a done bit or an error bit set in SEC Interrupt Status Register
High (SISRH). When I hit a break point in Debug using CodeWarrior 6.4's
View \ Register Details, I can see my first Descriptor in the
Crypto-Channel Descriptor Buffer for Channel Zero (CBUF0) but it will
not move on to the next Descriptor in the chain even though the Pointer
to the "Next Descriptor" in the chain looks correct to me. And the
CCPSRH0 seems to be stuck in state 0x1B.
Also do Crypto-Channel Zero and channel One really share the same
Descriptor Buffer MBAR+ 0x22080-0x220BF ??? I'm only asking because I
think I've found an error in Rev 4 of the Reference manual. See the
link above for more on that.
I sure could use a nudge in the right direction.
Thanks for any advice you can give me on this.
James
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Copyright (c) 2009, Baker Hughes Incorporated. All rights reserved.
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<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
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From:</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> =
<FONT SIZE=3D2 FACE=3D"Fixedsys">James Edwards =
<jamesDOTedwardsATcentriliftDOTcom></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Fixedsys"> To: =
[email protected]</FONT></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Fixedsys"> Subject: PROBLEM WITH LOADING =
PRODUCT</FONT></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Fixedsys"> </FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Fixedsys">Help with the SEC on an MCF5485</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Fixedsys"> -------------------------------------------------=
-------------</FONT></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">Hi WildeRice Gang,</FONT></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT SIZE=3D2 FACE=3D"Courier">This =
is my first post. I was pointed here by Bob McMillan at Future =
Electronics. He said a lot of good things about the =
list.</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT SIZE=3D2 FACE=3D"Courier">My =
Problem is that I’m having some grief figuring out how to use the =
Security Encryption Controller (SEC) on the MCF5485.</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">I’ve asked</FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">for some help</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">on =
the</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">FreeScale Forum but have =
not</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">received any so =
I’m sending this to out you. In the hope that some of you have =
already conquered the SEC. I would like to use the SEC to =
calculate an MD5 check sum for a file.</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">You can check out my post</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Courier">,</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"><FONT SIZE=3D2 FACE=3D"Courier"> and all my replied to =
myself on the FreeScale Message board at the link below (I Hope it is OK =
to link to their message board on the wildrice list)</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><A =
HREF=3D"http://forums.freescale.com/freescale/board/message?board.id=3DCF=
COMM&thread.id=3D6638"><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"><U><FONT COLOR=3D"#0000FF" SIZE=3D2 =
FACE=3D"Courier">http://forums.freescale.com/freescale/board/message?boar=
d.id=3DCFCOMM&thread.id=3D6638</FONT></U></SPAN><SPAN =
LANG=3D"en-us"></SPAN></A><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">I’ve pasted a few snippets of C code in =
there. It’s getting</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">too</FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">long to paste into an email. </FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">If you want</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">to / need to =
see</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">the source files let me =
know and I’ll send them to you.</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">As of today I’ve =
stopped</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">statically assigning =
both Crypto channels to the MDEU during initialization because I was =
getting a channel already assigned error. I think the Header for =
the first Descriptor just goes out and grabs the MDEU if it is not =
already in use anyway.</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">Now</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Courier"> I’m stuck just after loading Fetch Register Zero =
(FR0) with a pointer to the Head of my first</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">Descriptor (</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Courier">the</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">Descriptor</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">structure and how I</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT SIZE=3D2 =
FACE=3D"Courier">’</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"><FONT SIZE=3D2 FACE=3D"Courier">m building the Descriptor =
chain are on the link above)</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">I’m not seeing a done bit or an error bit set =
in</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">SEC</FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">Interrupt Status Register High (SISRH). When =
I</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">hit a</FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">break point in Debug using CodeWarrior 6.4’s =
View</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">\</FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">Register Details,</FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">I can</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">see my first Descriptor =
in the</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">Crypto-Channel =
Descriptor Buffer for Channel Zero (CBUF0) but it will not move on to =
the next Descriptor in the chain even though the Pointer to =
the</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">“Next =
Descriptor” in the chain looks correct to me. And =
the</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">CCPSRH0 seems to be =
stuck in state 0x1B.</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">Also do</FONT></SPAN><SPAN =
LANG=3D"en-us"><FONT FACE=3D"Courier"></FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">Crypto-Channel</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">Zero and =
channel</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">One really share the =
same Descriptor</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 =
FACE=3D"Courier">Buffer</FONT></SPAN><SPAN LANG=3D"en-us"><FONT =
FACE=3D"Courier"></FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"> <FONT SIZE=3D2 FACE=3D"Courier">MBAR+ 0x22080-0x220BF =
??? I’m only asking because I think I’ve found an =
error in Rev 4 of the Reference manual. See the link above for =
more on that.</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Courier">I sure could use a nudge in the right =
direction.</FONT></SPAN><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"><FONT FACE=3D"Courier">Thanks for any =
advice you can give me on this.</FONT></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN =
LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"><FONT =
SIZE=3D2 FACE=3D"Arial">James</FONT></SPAN><SPAN =
LANG=3D"en-us"></SPAN><SPAN LANG=3D"en-us"></SPAN></P>
<P DIR=3DLTR><SPAN LANG=3D"en-us"></SPAN><SPAN =
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FACE=3D"Arial">THIS EMAIL AND ANY ATTACHED FILES ARE CONFIDENTIAL AND =
MAY BE LEGALLY PRIVILEGED. If you are not the addressee, any disclosure, =
reproduction, copying, distribution, or other dissemination or use of =
this communication is strictly prohibited. If you have received this =
transmission in error please notify the sender immediately and then =
delete this email.</FONT></SPAN></I></P>
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LANG=3D"en-us"><I></I></SPAN><I><SPAN LANG=3D"en-us"><FONT SIZE=3D1 =
FACE=3D"Arial">Copyright © 2009, Baker Hughes Incorporated. All =
rights reserved.</FONT></SPAN></I><SPAN =
LANG=3D"en-us"><I></I></SPAN><SPAN LANG=3D"en-us"><I></I></SPAN><I><SPAN =
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