Re: ISR Function

Hi,

I think I was unable to put my question. Sorry for that, here it is:

My code is like this:

main()
{

function1(); // this will execute and output of this function is x,y 
             //which are global variables.
}
Now my DAC(x,y) function will take this x,y as input.I am trying to 
execute this DAC(x,y) function at every 100 milisec, nomatter where I 
am in the main loop at that time.
I am using COdeWarrior Compiler 8.1.

-regards
Rajesh





--- In [email protected], "Dobbin Allan-r11834" 
<Allan.Dobbin@...> wrote:
>
> Rajesh, perhaps I don't understand your question - do you have PIT
> working and interrupting, but you just don't know how to call a C
> function from assembler?
>  
> Most compilers allow you to specify a function is an interrupt 
function,
> i.e. with Diab compiler you can do the following:
>  
> INTERRUPT void external_interrupt (void)
> {
>     "
>     "
>     PitIsr ();    /* handle PIT interrupt */
> }
>  
> so in your vector area, you have
>  .org base_add + 0x500  ;External Interrupt Exception
>  b external_interrupt
> 
> So now calling your DAC function within PitIsr is just like any 
other C
> code i.e. DAC(x,y);
>  
> The question of where do x,y come from within an ISR - perhaps 
these are
> global variables?
>  
> I'm not sure if this is what you were asking.
>  
> - Allan   
> 
>  
>  
> 
> 	-----Original Message-----
> 	From: [email protected] [mailto:[email protected]] 
On
> Behalf Of Rajesh
> 	Sent: Thursday, June 29, 2006 4:21 AM
> 	To: [email protected]
> 	Subject: [MPC500] ISR Function
> 	
> 	
> 
> 	
> 	Hi everyone,
> 	I am working with MPC566 and I have a function DAC(x,y), 
> 	i.e. a D/A converter function, which I want to execute on
> Interrupt 
> 	at every 100 ms.
> 	I am using a PIT and can set time between 64 msecs to 4.19 
secs.
> 	Can anyone please tell me how to call this function in an ISR?
> 	
> 	-regards
> 	Rajesh
> 	
> 	
> 
> 	 
> 
> 
> 
> [Non-text portions of this message have been removed]
>







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