RE: how to escape forward slash?

Hello Vawter,

It does not work for me, I tried exactly that already.

But I do not understand what you mean by 1.42???=20
since jakarta regexp latest release is 1.3 ...
if you mean 1.4x as JSE then I would not be using
jakarta regexp at all, I need regexp jakarta because
I am tied to using JVM 1.3x only.

Additionally I can not hardcode the replacing=20
within the java code because we have a large list
of transformation patterns that must be updateable=20
without having to modify, recompile and redeploy the
java files, the transformation patterns (thesaurus)=20
is included separately as a text (configuration) file.

Thanks in advance,
Best Regards,
Giovanni

> -----Original Message-----
> From: Don Vawter [mailto:[email protected]]
> Sent: Wednesday, November 10, 2004 5:18 PM
> To: Regexp Users List
> Subject: Re: how to escape forward slash?
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> I think you can use:
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>  / C[/]O / /
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> I haven't tested this but in 1.42    =20
> s.replaceAll("C/O","xxx") works fine
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> I haven't tested th
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> Giovanni Azua wrote:
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> >Hello all,
> >
> >Does anyone know how to escape forward
> >slash using jakarta regexp, the funny
> >thing is that sed understand well the
> >escaping of forward slash: \/ but regexp
> >does not.
> >
> >e.g. when providing the pattern:
> >
> >/ C\/O / /
> >
> >I get the following error:
> >
> >org.apache.regexp.RESyntaxException: Syntax error: Escape=20
> terminates string
> >...
> >PATTERN ERROR in line: / C\/O / /
> >
> >Thanks in advance,
> >
> >Best Regards,
> >Giovanni
> >
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> >
> > =20
> >
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