Re: Process parent of a subflow
David Simón <[email protected]>
| Newsgroups | gmane.comp.java.enhydra.shark |
|---|---|
| Message-ID | <[email protected]> |
Thank you Sasa, that is perfect.
Best regards,
David.
>
> Hi,
>
> just use:
>
> WfProcess parent;
> WfRequester req=proc.requester();
> if (req instanceof WfActivity) {
> parent=((WfActivity)req).container();
> }
>
> Regards,
> Sasa.
>
>
> ----- Original Message -----
> From: David Simón
> To: [email protected]
> Sent: Monday, June 27, 2005 5:11 PM
> Subject: Re: [shark] Registering process on the fly
> (performance)
>
>
> Hi,
>
> In Shark 1.0, is there any way to know which is the process
> parent instance of a subflow?
>
> Best regards.
>
> David.
>
> > Hi,
> >
> > uploading new XPDL into shark is expensive operation. However, in shark1.1 it is up to 5 times faster than in shark1.0, depending on
> > XPDL.
> >
> > Normal use case would be to have all XPDLs you need imported, and than to create process instances based on their processes. Than,
> > the creation of the process instance should be very fast, and is measured in milliseconds.
> >
> > There is no way to "register" package otherwise than using PackageAdministration, nor to create process instance without having
> > package "registered".
> >
> > Regards,
> > Sasa.
> >
> > ----- Original Message -----
> > From: "Igor" <[email protected]>
> > To: <[email protected]>
> > Sent: Monday, June 27, 2005 2:41 PM
> > Subject: [shark] Registering process on the fly (performance)
> >
> >
> > > Hi,
> > > Description: I create small process in runtime (as xpdl file), then
> > > register it in Shark (PackageAdministration.openPackage()), then execute
> > > it.
> > > It works fine, but has poor (for my purpose) performance. Registering
> > > package (1 process that has 1 activity) takes ~500 ms (2.4 mhz 1gb)
> > > Can you advice, please, how can Shark may be tuned? Or may be exists
> > > some way to register package without create.xpdl first - create Process
> > > in programmatic way?
> > >
> > > Thank you,
> > > Igor Laberov
> > >
> > >
> > >
> >
> >
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