[jgroups-users] suggestions for working with OpenStack (NAT question)

Questions/problems related to using JGroups <[email protected]> Mon, 20 Jan 2020 12:55:46 -0500
Newsgroups gmane.comp.java.javagroups.general
Message-ID <mailman.34257.1579544419.1370.javagroups-users@lists.sourceforge.net>
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Hi,

A customer wants to use our product on OpenStack, which (I assume you know)
has private addresses for every node and then a floating IP address which
can be reached everywhere. So they have nodes "not on the same network, on
different cloud providers / zones with incompatible addresses scheme."

We're using a tcp stack, jgroups 4.1.8, and TCP#bind_addr has to be set to
the local, private, address or else jgroups can't bind to it. But then
other nodes can't reach that node. Do you have suggestions about how to
make this work?

I don't have access to an OpenStack setup like this to test; I can only
test in one region, so I don't know if using floating IPs for
TCPPING#initial_hosts should work or not for the nodes to find each other.
(If so, that's great, but would mean a lot of work for us to have the nodes
carry around a 2nd IP address to pass to each other for other reasons.)

Thanks,
Bobby

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<div dir=3D"ltr">Hi,<div><br></div><div>A customer wants to use our product=
 on OpenStack, which (I assume you know) has private addresses for every no=
de and then a floating IP address which can be reached everywhere. So they =
have nodes &quot;not on the same network, on different cloud providers / zo=
nes with incompatible addresses scheme.&quot;</div><div><br></div><div>We&#=
39;re using a tcp stack, jgroups 4.1.8, and TCP#bind_addr has to be set to =
the local, private, address or else jgroups can&#39;t bind to it. But then =
other nodes can&#39;t reach that node. Do you have suggestions about how to=
 make this work?</div><div><br></div><div>I don&#39;t have access to an Ope=
nStack setup like this to test; I can only test in one region, so I don&#39=
;t know if using floating IPs for TCPPING#initial_hosts should work or not =
for the nodes to find each other. (If so, that&#39;s great, but would mean =
a lot of work for us to have the nodes carry around a 2nd IP address to pas=
s to each other for other reasons.)</div><div><br></div><div>Thanks,</div><=
div>Bobby</div><div><br></div></div>

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