Re: [jgroups-users] up() method in protocol stack
Questions/problems related to using JGroups <[email protected]> Sun, 12 Mar 2017 17:29:21 +0100
| Newsgroups | gmane.comp.java.javagroups.general |
|---|---|
| Message-ID | <[email protected]> |
The behavior is described in [1]. Regular messages by the same sender are delivered one-by-one. Messages by different senders or OOB messages are delivered in parallel. [1] http://www.jgroups.org/manual4/index.html#_message_delivery_and_ordering On 12/03/17 16:00, Questions/problems related to using JGroups wrote: > Hi All, > > Assume we have the following scenario: > we have messages m1 and m2 are received by transport protocol (UDP). Frist > of all, UDP will be handed m1 up the protocol stack until it reaches the > topmost protocol (targeted layer) and invokes the up() method of topmost > protocol. > > The question is: > > When does m2 send up the protocol stack? Does m2 send up the protocol stack > just when up() method of topmost protocol invokes/get return? Or Does m2 > send up the protocol stack just when up() method for the first layer that > above the transport protocol (UDP) is called? > Note that in this scenario assume we do not use bundle message. > > Ibrahim > > > > -- > View this message in context: http://jgroups.1086181.n5.nabble.com/up-method-in-protocol-stack-tp11295.html > Sent from the JGroups - General mailing list archive at Nabble.com. > > ------------------------------------------------------------------------------ > Announcing the Oxford Dictionaries API! The API offers world-renowned > dictionary content that is easy and intuitive to access. Sign up for an > account today to start using our lexical data to power your apps and > projects. Get started today and enter our developer competition. > http://sdm.link/oxford > _______________________________________________ > javagroups-users mailing list > [email protected] > https://lists.sourceforge.net/lists/listinfo/javagroups-users > -- Bela Ban, JGroups lead (http://www.jgroups.org) ------------------------------------------------------------------------------ Announcing the Oxford Dictionaries API! The API offers world-renowned dictionary content that is easy and intuitive to access. Sign up for an account today to start using our lexical data to power your apps and projects. Get started today and enter our developer competition. http://sdm.link/oxford