[JXTA discuss] How do I manually start a resolver service
[email protected] Wed, 30 Mar 2005 22:04:32 +0000
| Newsgroups | gmane.comp.java.jxta.devel,gmane.comp.java.jxta.general |
|---|---|
| Message-ID | <033020052204.1337.424B2270000A14B1000005392205886442010E09970E9D__45617.3310791657$1112220668$gmane$org@comcast.net> |
Hi, I have created a JXTA service and added it to a new peergroup and started that peergroup. Then, I successfully lookupService(new service). The purpose of the new services is to pass messages between two peers. However, message are lost. I guess that the resolver services is not started on the new peergroup that I created. see message. <WARN 2005-03-30 15:49:21,152 DiscoveryServiceImpl::getRemoteAdvertisements:291> resolver has not started yet, query discarded. <WARN 2005-03-30 15:58:40,788 ResolverServiceImpl::processSrdi:1051> No srdi handler registered :urn:jxta:uuid-DEADBEEFDEAFBABAFEEDBABE0000000305 But, I don't know how to manually started the ResolverService on a new peergroup. Or, that may not be the problem. Does anyone have good ideas or explainations for it. Thanks, -Ray