RE: Peers do not find each other

Matthias,

In my setup, I do not explicitly set any peer as a rdv, but rather after
a period of about 2 minutes, one of my peers becomes and
AUTO_RENDEZVOUS.  I typically wait until the one peer becomes a rdv
before starting up another, so I don't know what will happen if I start
multiple nodes at the same time so that a rdv is not available on
loadup.  I suspect that one of them will become a rdv and all will work
fine.  I will test this scenario tomorrow and get back to you.

I think if you play with your configuration, you should be able to get
it working without explicitly setting a peer to rdv.  You might search
the list for the subject "MyJXTA configuration"... There might be
something useful there for you.

Hth

Paul

-----Original Message-----
From: Matthias Horst [mailto:[email protected]] 
Sent: Tuesday, August 09, 2005 4:42 PM
To: [email protected]
Subject: Re: [JXTA user] Peers do not find each other


Hi friends,

I searched a little bit more on the mailing list and found out that I 
really need to have a rdv service. So I added to my program an explizit 
call to start a rendezvous service (the code is below). But still a 
second peer (at the same switch) does not find the first peer.

Btw. the peerGroup I pass over is the global netPeerGroup.

greetings

Matthias



     public boolean waitForRendezVous(PeerGroup peerGroup) throws 
Exception {
         RendezVousService rdv = peerGroup.getRendezVousService();
         if (rdv.isRendezVous()) {
             return true;
         }
         if (rdv.isConnectedToRendezVous()) {
             return true;
         }

	//waiting for rdvs 20secs
         int count = 0;
         while (!rdv.isConnectedToRendezVous() && !rdv.isRendezVous()) {
             Thread.sleep(1 * 1000);
             if (++count >= 20) {
                 break;
             }
         }

	// expl. start the rdv service
         rdv.startRendezVous();

	// check again
         count = 0;
         while (!rdv.isConnectedToRendezVous() && !rdv.isRendezVous()) {
             Thread.sleep(1 * 1000);
             if (++count >= 5) {
                 break;
             }
         }

         return rdv.isConnectedToRendezVous();
     }


Matthias Horst wrote:

> Hi,
> 
> Background:
> ------------
> I try to connect two peers, call them peer A and peer B,  which are
> plugged in at the same router. I do *not* configure any rendezvous 
> peers, because for my projekt a want to give away just a CD with the 
> Peer-2-Peer Software and everybody in the same network, who uses the
CD, 
> should find all the other users automatically, without asking a 
> administrator for settings. (At least that's the idea)
> 
> Settings:
> -----------
> As a special I set the rendezvous seed peers to something stupid, e.g.
> tcp://127.0.0.1:19999, because if I leave this option empty, it always

> tries to connect automatically to the official jxta.org rendezvous
peers 
> what I don't want. I do *not* enable the option "use only configured 
> seed peers" such that it should also look for lokal rendezvous via 
> multicast. Btw. TCP and Multicast is enabled. All firewalls are 
> disabled. My program waits 20 seconds in order to find a rdvs or to 
> become a rdvs by itself (this is made by a piece of code Muhamed 
> committed to the mailing list ...)
> 
> Experiment:
> ------------
> With these settings peer A and peer B don't find each other. Moreover
> the program does not say that it has become a rdvs by itself.
> 
> Now I configure peer A as a rendezvous and restart it without 
> restarting
> peer B (the edge peer).
> 
> Again they don't find each other.
> 
> Now I restart peer B (the edge peer).
> 
> Again they don't find each other.
> 
> Now I configure peer B to use peer A as a rendezvous (seed rendezvous)
> and restart it without restarting peer A.
> 
> Now everything works fine!
> 
> Then I stop peer A (the rendezvous) and restart it.
> 
> Again they don't find each other.
> 
> Question:
> ------------
> Is anybody out there who can explain this behaviour? I thought that at
> least in the same subnet all peers find each other automatically as
long 
> as multicast is enabled even without an explicit rdv peer. Obviously
as 
> soon as peer A is offline for some seconds every communication between
A 
> and B seems to be impossible. I don't think that you guys out there
are 
> using a p2p network where everybody must reboot his application
because 
> somebody else shutdown his peer ;) So what's the trick?
> 
> 
> 
> greetings
> 
> 
> 
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                                              Software Solutions GmbH
Matthias Horst 

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