RE: Individual Members of PeerGroup

Thanks Vitaly,
 
The only problem with that solution is that I don't know ahead of time
who I want to send it to...  If there are 10 in a group, I want to
randomly send the message to a few of them... alternating the recipients
each time.  I can't do that with the propagate pipe solution below.  
 
Do you have any insight about propagate(Enumeration destPeerIds, Message
msg, String serviceName, String serviceParam, int ttl)?
 
Thanks,
 
Paul

	-----Original Message-----
	From: Vitaly Vainer [mailto:[email protected]] 
	Sent: Thursday, September 08, 2005 7:05 AM
	To: [email protected]
	Subject: RE: [JXTA user] Individual Members of PeerGroup
	
	

	Hi Paul,

	 

	You may create input pipe with the same id on the peers you
would like to get your message and then use propagate output pipe with
chosen id to send message to all of them.

	 

	Create input pipe:

	            byte [] CHOSEN_ID = new byte [] {...};  // your
chosen id for pipes

	            ...

	            PeerGroup _group;  // your peer group

	            ...

	PipeAdvertisement pipeAd = (PipeAdvertisement)
AdvertisementFactory.newAdvertisement(PipeAdvertisement.getAdvertisement
Type());       

	
pipeAd.setPipeID(IDFactory.newPipeID(_group.getPeerGroupID(),
CHOSEN_ID));

	            pipeAd.setType(_PipeService.PropagateType);   

	            IntputPipe pipe =
_group.getPipeService().createIntputPipe(pipeAdv, new PipeMsgListener ()
{

	                                    public void
pipeMsgEvent(PipeMsgEvent event)

	                                    {

	                                                // Do whatever
you need when getting new message

	}

	})

	 

	Create output pipe:

	PipeAdvertisement pipeAd = (PipeAdvertisement)
AdvertisementFactory.newAdvertisement(PipeAdvertisement.getAdvertisement
Type());       

	
pipeAd.setPipeID(IDFactory.newPipeID(_group.getPeerGroupID(),
CHOSEN_ID));

	            pipeAd.setType(_PipeService.PropagateType);   

	            OutputPipe pipe =
_group.getPipeService().createOutputPipe(pipeAdv, PIPE_TIMEOUT)

	 

	 

	 

	Vitaly Vainer,

	Content Objects, Israel.

	 

	
  _____  


	From: Poole, Paul P1 [mailto:[email protected]] 
	Sent: Wednesday, September 07, 2005 10:38 PM
	To: [email protected]
	Subject: [JXTA user] Individual Members of PeerGroup

	 

	Hi all... 

	I was wondering if some of you could enlighten me on the best
way to send a message to only a few members of a peer group.  I don't
want to propagate the message to every member of a group, just a few of
them.  I know that RendezVousService has a couple of methods that could
work... 

	One possibility is to use propagateInGroup() with a low TTL
(like 1), but that will probably send to more peers than desired.  

	Another possibility, is to get an enumeration of the peerIDs
currently connected to the rendezvous and then use a subset of that with
the RendezvousService method propagate(Enumeration destPeerIds, Message
msg, String serviceName, String serviceParam, int ttl).  However, the
API states that this method is very expensive. Is it still expensive if
I only use 2 or 3 peers?

	Are there are any better solutions? 

	Thanks in advance for your insight! 

	Paul Poole
	Software Engineer
	Lockheed Martin 

	 


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