RE: Individual Members of PeerGroup

When you used it, did you use it for a subset of the members or did you
use it to propagate messages to all of the members?  My thought is that
if I use it for only a few members, then it shouldn't be too expensive.
 
Thanks for your help...
 
Paul

	-----Original Message-----
	From: Vitaly Vainer [mailto:[email protected]] 
	Sent: Thursday, September 08, 2005 7:29 AM
	To: [email protected]
	Subject: RE: [JXTA user] Individual Members of PeerGroup
	
	

	It worked for me; I never did load/performance tests of it.

	 

	Vitaly.

	
  _____  


	From: Poole, Paul P1 [mailto:[email protected]] 
	Sent: Thursday, September 08, 2005 2:22 PM
	To: [email protected]
	Subject: RE: [JXTA user] Individual Members of PeerGroup

	 

	Thanks Vitaly,

	 

	The only problem with that solution is that I don't know ahead
of time who I want to send it to...  If there are 10 in a group, I want
to randomly send the message to a few of them... alternating the
recipients each time.  I can't do that with the propagate pipe solution
below.  

	 

	Do you have any insight about propagate(Enumeration destPeerIds,
Message msg, String serviceName, String serviceParam, int ttl)?

	 

	Thanks,

	 

	Paul

		-----Original Message-----
		From: Vitaly Vainer [mailto:[email protected]] 
		Sent: Thursday, September 08, 2005 7:05 AM
		To: [email protected]
		Subject: RE: [JXTA user] Individual Members of PeerGroup

		Hi Paul,

		 

		You may create input pipe with the same id on the peers
you would like to get your message and then use propagate output pipe
with chosen id to send message to all of them.

		 

		Create input pipe:

		            byte [] CHOSEN_ID = new byte [] {...};  //
your chosen id for pipes

		            ...

		            PeerGroup _group;  // your peer group

		            ...

		PipeAdvertisement pipeAd = (PipeAdvertisement)
AdvertisementFactory.newAdvertisement(PipeAdvertisement.getAdvertisement
Type());       

	
pipeAd.setPipeID(IDFactory.newPipeID(_group.getPeerGroupID(),
CHOSEN_ID));

		            pipeAd.setType(_PipeService.PropagateType);


		            IntputPipe pipe =
_group.getPipeService().createIntputPipe(pipeAdv, new PipeMsgListener ()
{

		                                    public void
pipeMsgEvent(PipeMsgEvent event)

		                                    {

		                                                // Do
whatever you need when getting new message

		}

		})

		 

		Create output pipe:

		PipeAdvertisement pipeAd = (PipeAdvertisement)
AdvertisementFactory.newAdvertisement(PipeAdvertisement.getAdvertisement
Type());       

	
pipeAd.setPipeID(IDFactory.newPipeID(_group.getPeerGroupID(),
CHOSEN_ID));

		            pipeAd.setType(_PipeService.PropagateType);


		            OutputPipe pipe =
_group.getPipeService().createOutputPipe(pipeAdv, PIPE_TIMEOUT)

		 

		 

		 

		Vitaly Vainer,

		Content Objects, Israel.

		 

		
  _____  


		From: Poole, Paul P1 [mailto:[email protected]] 
		Sent: Wednesday, September 07, 2005 10:38 PM
		To: [email protected]
		Subject: [JXTA user] Individual Members of PeerGroup

		 

		Hi all... 

		I was wondering if some of you could enlighten me on the
best way to send a message to only a few members of a peer group.  I
don't want to propagate the message to every member of a group, just a
few of them.  I know that RendezVousService has a couple of methods that
could work... 

		One possibility is to use propagateInGroup() with a low
TTL (like 1), but that will probably send to more peers than desired.  

		Another possibility, is to get an enumeration of the
peerIDs currently connected to the rendezvous and then use a subset of
that with the RendezvousService method propagate(Enumeration
destPeerIds, Message msg, String serviceName, String serviceParam, int
ttl).  However, the API states that this method is very expensive. Is it
still expensive if I only use 2 or 3 peers?

		Are there are any better solutions? 

		Thanks in advance for your insight! 

		Paul Poole
		Software Engineer
		Lockheed Martin 

		 

		 

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07/09/2005