Re: Sockets and Groups

Sorry Eugenio, maybe I wasn't clear. I meant, what is the membership  
service being used by the group? If  you created the group  
advertisement (advPG) from the all purpose peer group implementation  
advertisement, then I think it has a null membership service by  
default. (Perhaps you could send the peer group advertisement so we  
can see for sure.) I'm guessing that's why the peers can communicate  
without having to "join" the group explicitly. Maybe someone else  
knows for sure...

Vanessa

On 20-Feb-06, at 3:36 PM, Eugenio Flores wrote:

>
>
> Well, I don't use any membership service. In both application use  
> the same group advertisement to instantiate a peer object in order  
> to use it as a parameter when I declare, both, JxtaServerSocket and  
> the JxtaSocket.
>
> Like this:
> //Server socket side//////////////////////////
>
> pg = myGroup.newGroup(advPG);
> serverSocket = new JxtaServerSocket(pg, this.pipeAdv,10);
>
> //JxtaSocket side////////////////////////////////////////////////
>  socket = new JxtaSocket(pg,
>                                 //no specific peerid
>                                 null,
>                                 pipeAdv,
>                                 //general TO: 30 seconds
>                                 30000,
>                                 // reliable connection
>                                 true);
>
>
> Vanessa Williams <[email protected]> escribió:
> Hi Eugenio,
>
> interesting situation. Does the group you created have a null  
> membership service? In other words, maybe everyone is automatically  
> authorized for the group without having to log in? It's just a  
> thought...
>
> Vanessa
>
> On 20-Feb-06, at 1:51 PM, Eugenio Flores wrote:
>
>> Hello Group.
>>
>> I got a conceptual doubt about joining groups and JXTASockets:
>>
>> I have two applications (You know that already), the first one has  
>> a JxtaServerSocket, but first it creates a group. Then I declare  
>> the JxtaServerSocket in the scope of this group, instead of doing  
>> it in the scope of the netGroup:
>>
>> myGroup = PeerGroupFactory.newNetPeerGroup();
>> private PeerGroup pg = null;
>> private PeerGroupAdvertisement advPG = null;//I assign advPG when  
>> I look for the group advertisement locally
>> JxtaServerSocket serverSocket;
>> pg = myGroup.newGroup(advPG);
>> serverSocket = new JxtaServerSocket(pg, this.pipeAdv,10);
>>
>> The other application has a JxtaSocket, but first it finds the  
>> group advertisement published by t he first application, afterward  
>> it instantiates that group. Finally I create the JxtaSocket in the  
>> scope of this group.
>>
>>  socket = new JxtaSocket(pg,
>>                                 //no specific peerid
>>                                 null,
>>                                 pipeAdv,
>>                                 //general TO: 30 seconds
>>                                 30000,
>>                                 // reliable connection
>>                                 true);
>>
>> Bo th application work fine, they communicate with each other  
>> well, but the second application did not have to join the group  
>> created in the JXTAServer application. As I told you, I just  
>> instantiate! , in the second application, the group that it finds  
>> and creates the JxtaSocket with this group. So now I wonder in  
>> what kind of cases it is necessary to join a group.
>>
>> Could you help me with this doubt?
>>
>> Thanks a lot again.
>>
>>
>>
>> Do You Yahoo!? La mejor conexión a Internet y 2GB extra a tu  
>> correo por $100 al mes. http://net.yahoo.com.mx
>
> --
> Vanessa Williams
> Oponia Networks
> [email protected]
>
>
>
>
>
> Do You Yahoo!? La mejor conexión a Internet y 2GB extra a tu correo  
> por $100 al mes. http://net.yahoo.com.mx

--
Vanessa Williams
Oponia Networks
[email protected]