Re: CTM + re

Sorry, just replied to the wrong mail.

From: <MacGregor>, Duncan MacGregor <[email protected]<mailto:[email protected]>>
Date: Thursday, 18 September 2014 14:48
To: FDnC Red <[email protected]<mailto:[email protected]>>, Post all your questions about iText here <[email protected]<mailto:[email protected]>>
Subject: Re: [iText-questions] CTM + re

Yeah, found it. I’ll get right on it as soon as my machine has finished rebooting (my entire machine froze, so I think I beat your app crashes :-) ).

From: FDnC Red <[email protected]<mailto:[email protected]>>
Reply-To: FDnC Red <[email protected]<mailto:[email protected]>>, Post all your questions about iText here <[email protected]<mailto:[email protected]>>
Date: Thursday, 18 September 2014 14:35
To: "[email protected]<mailto:[email protected]>" <[email protected]<mailto:[email protected]>>
Subject: [iText-questions] CTM + re

Two questions.  1) Am I transforming this rectangle by the matrix correctly?  2) Is there an easier way?

The Content Stream
q
1.1342565 0 0 1.199793 0 0 cm
41.906 201.086 0.936 -69.448 re
f
Q

float rectXPt = ((PdfNumber)operands[0]).FloatValue; //41.906
float rectYPt = ((PdfNumber)operands[1]).FloatValue; //201.086
float rectWidthPt = ((PdfNumber)operands[2]).FloatValue; //0.936
float rectHeightPt = ((PdfNumber)operands[3]).FloatValue; //-69.48

//Translate based on transformation matrix
//x1 = a * x + c * y + e
//y1 = b * x + d * y + f

//a = 1.1342565
//b = 0
//c = 0
//d = 1.199793
//e = 0
//f = 0

float transStartXPt = m[0] * rectXPt + m[3] * rectYPt + m[6];
float transStartYPt = m[1] * rectXPt + m[4] * rectYPt + m[7];
float tempEndXPt = rectXPt + rectAbsWidthPt;
float tempEndYPt = rectYPt + rectAbsHeightPt;
float transEndXPt = m[0] * tempEndXPt + m[3] * tempEndYPt + m[6];;
float transEndYPt = m[1] * tempEndXPt + m[4] * tempEndYPt + m[7];


Thanks,
Darren

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