Re: termination question

Hello Andreas,

Yes, but putting an explicit lock in sfTerminate method of component A 
till the event task finishes, SF can wait for the termination of A.

Thanks & Regards,
Ritu.

Andreas Unterkircher wrote:

> Hi Ritu,
> termination means calling the sfTerminate method, I think. So if A has 
> some lock variable that would cause sfTerminate to just wait until the 
> task caused by the event is finished, this would cause SF to "wait" 
> with  termination of A ?
>
> Best regards,
> Andreas
>
> Ritu Sabharwal wrote:
>
>> Hi Andreas,
>>
>> In case of Compound, if any child terminates it notifies the parent 
>> which in turn terminates all other children and then itself. So in 
>> your case, SF will not wait for A to finish its task, it will 
>> terminate it immediately as soon as B terminates.
>>
>> Thanks & Regards,
>> Ritu.
>>
>> Andreas Unterkircher wrote:
>>
>>> Hello,
>>>
>>> I have a question concerning termination. Suppose I have a compound  
>>> containing 2 components:
>>>
>>> Compound  {
>>>  A;
>>>  B; }
>>>
>>> A extends EventCompoundImpl. B terminates and in its sfTerminate  
>>> method it sends an event to A which causes A to do some task that  
>>> take some time.  If B terminates, what happens to A ? Would SF wait  
>>> until A finishes the task triggered by B's message ? Or would it 
>>> just  terminate A ?
>>>
>>> Thanks,
>>> Andreas
>>>
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>>
>>
>
>



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