Re: giving delayed response
Nic Ferrier <[email protected]>
| Newsgroups | gmane.comp.java.sun.servlet |
|---|---|
| Message-ID | <[email protected]> |
Madhu Vadlapudi <[email protected]> writes: > Hello Friends, > > In my servlet program i am trying to send a message to the client before > completion of servicing the request completly. Some more elobaration... > > > public void doGet(HttpServletRequest request, > HttpServletResponse response) > throws IOException, ServletException > { > PrintWriter out = response.getWriter(); > > // This is the message that i have to give to the client. > out.println("<html>"); > out.println("<body>"); > out.println("Processing your request.."); > out.println("</body>"); > out.println("</html>"); > > //Then i will call the apropriate function that > // serves the request of the client > //Then i am writing the out put to a file 'FileName' > > // .... processing .... > > //Redirecting to the client > > response.sendRedirect(FileName); > } > > Here i am unable to see the message (which should be "Processing your > request..." ) when i test this servlet. What might be the reason, if anybody > has the script or any source code or suggestions please let me know. > You can't do this. HTTP is not a session based protocol, it executes things in batches. See the archives of this list for more discussion about this subject. Nic Ferrier ___________________________________________________________________________ To unsubscribe, send email to [email protected] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html